For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)a) (1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/

(1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/A))

For an ideal non-inverting operational amplifier having finite gain (

1.	For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)a) (1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/
A.	(1+R2/R1)/(1+((1+R2/R1)/A))
B.	(R2/R1)/(((1+R2/R1)/A))
C.	(1+R2/R1)/(((1+R2/R1)/A))
D.	(R2/R1)/(1+((1+R2/R1)/A))
E.	(1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/A))
Answer» B. (R2/R1)/(((1+R2/R1)/A))

Discussion

No Comment Found

Related MCQs

Consider the figure given below. If the resistance R1 is disconnected from the ground and connected to a third power source v3, then expression for the value ofv0 is
It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 MΩ to a load of 1-kΩ resistance. Find the load voltage if the connection is done (a) directly and (b) through a unity-gain voltage follower.
For designing a non-inverting amplifier with a gain of 2 at the maximum output voltage of 10 V and the current in the voltage divider is to be 10 μA the resistance required are R1 and R2 where R2 is used to provide negative feedback. Then
The finite voltage gain of a non-inverting operational amplifier is A and the resistance used is R1 and R2 in which R2 is the feedback resistance. Under what conditions it can one use the expression 1 + R2/R1 to determine the gain of the amplifier?
While performing an experiment to determine the gain for an ideal operational amplifier having finite gain, a student mistakenly used the equation 1 + R2/R1 where R2 is the feedback resistance. What is the percentage error in his result? Given A is the finite voltage gain of the ideal amplifier used.
The gain for an ideal non-inverting operational amplifier is (given R2 is the feedback resistance)
For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)a) (1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/
IT_IS_REQUIRED_TO_CONNECT_A_TRANSDUCER_HAVING_AN_OPEN-CIRCUIT_VOLTAGE_OF_1_V_AND_A_SOURCE_RESISTANCE_OF_1_M‚ÂÀ√≠¬¨¬©_TO_A_LOAD_OF_1-K‚ÂÀ√≠¬¨¬©_RESISTANCE._FIND_THE_LOAD_VOLTAGE_IF_THE_CONNECTION_IS_DONE_(A)_DIRECTLY_AND_(B)_THROUGH_A_UNITY-GAIN_VOLTAGE_FOLLOWER.?$#
For designing a non-inverting amplifier with a gain of 2 at the maximum output voltage of 10 V and the current in the voltage divider is to be 10 ‚âà√≠¬¨‚à´A the resistance required are R1 and R2 where R2 is used to provide negative feedback. The?#
Which of the following is not true for a voltage follower amplifier?

For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)a) (1+R2/R1)/(1+((1+R2/R1)/A))b) (R2/R1)/(((1+R2/R1)/A))c) (1+R2/R1)/(((1+R2/R1)/A))d) (R2/R1)/(1+((1+R2/R1)/

Discussion

No Comment Found

Related MCQs

Reply to Comment