MCQOPTIONS
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| 1. |
For a Wilkinson power divider of insertion loss L and the coupler is matched to the external circuitry, and then the gain of the coupler in terms of insertion loss is:$ |
| A. | 2L |
| B. | 1/2L |
| C. | L |
| D. | 1/L |
| Answer» C. L | |