For a given relation \(\sqrt {1 - {x^2}} + \sqrt {1 - {y^2}} = P\left( {x - y} \right)\), where P is a constant the value of \(\frac{{dy}}{{dx}}\) at point (0, 0) is

For a given relation \(\sqrt {1 - {x^2}} + \sqrt {1 - {y^2}} = P\left(

1.	For a given relation \(\sqrt {1 - {x^2}} + \sqrt {1 - {y^2}} = P\left( {x - y} \right)\), where P is a constant the value of \(\frac{{dy}}{{dx}}\) at point (0, 0) is
A.	-1
B.	0
C.	1
D.	-2
Answer» D. -2

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For a given relation \(\sqrt {1 - {x^2}} + \sqrt {1 - {y^2}} = P\left( {x - y} \right)\), where P is a constant the value of \(\frac{{dy}}{{dx}}\) at point (0, 0) is

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