 
			 
			MCQOPTIONS
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				| 1. | For a full wave rectification, in a low voltage ac voltmeter, the meter current can be expressed as | 
| A. | I<sub>o</sub> = (1.9 V<sub>in</sub>)/R<sub>1</sub> | 
| B. | I<sub>o</sub> = (3.9 V<sub>in</sub>)/R<sub>1</sub> | 
| C. | I<sub>o</sub> = (0.9 V<sub>in</sub>)/R<sub>1</sub> | 
| D. | I<sub>o</sub> = (2.9 V<sub>in</sub>)/R<sub>1</sub> | 
| Answer» D. I<sub>o</sub> = (2.9 V<sub>in</sub>)/R<sub>1</sub> | |