MCQOPTIONS
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MCQOPTIONS
| 1. |
For a full wave rectification, in a low voltage ac voltmeter, the meter current can be expressed a? |
| A. | I<sub>o</sub> = (1.9√óV<sub>in</sub>)/R<sub>1</sub> |
| B. | I<sub>o</sub> = (3.9√óV<sub>in</sub>)/R<sub>1</sub> |
| C. | I<sub>o</sub> = (0.9√óV<sub>in</sub>)/R<sub>1</sub> |
| D. | I<sub>o</sub> = (2.9√óV<sub>in</sub>)/R<sub>1</sub> |
| Answer» D. I<sub>o</sub> = (2.9‚Äö√†√∂‚àö‚â•V<sub>in</sub>)/R<sub>1</sub> | |