Find the sum of perimeters of an equilateral triangle and a regular pe – McqOptions

MCQOPTIONS

1.	Find the sum of perimeters of an equilateral triangle and a regular pentagon whose both side is 4 cm.
A.	36 cm
B.	62 cm
C.	32 cm
D.	252 cm
Answer» D. 252 cm

Discussion

No Comment Found

Related MCQs

<p>The ratio of inradius and circumradius of an equilateral triangle is:</p>
<p>In circular measure, the value of the angle 11<sup>0</sup>15 is : </p>
<p>If the area of a triangle is 1176 cm<sup>2</sup> and the ratio of base corresponding altitude is 3 : 4, then the altitude of the triangle is :</p>
<p>If the circumference of a circle increases from 4 to 8 , what change occurs in its area?</p>
<p>The radius of the incircle of a triangle is 2 cm. If the area of the triangle is 6 cm2. Then its perimeter is -</p>
<p>Let ABCD be a quadrilateral. Let the diagonals AC and BD meet at O. Let the perpendicular drawn from A to CD meet CD at E. Further, AO: OC = BO: OD, AB = 30 cm. CD = 40 cm. and the area of the quadrilateral ABCD is 1050 cm<sup>2</sup>. What is BE equal to?</p>
<p>In a triangle, two sides of 4 cm and 3 cm are at right angle. If the triangle is revolved along the 4 cm side, the curved surface area of the cone so formed will be</p>
<p>The volume of the largest right circular cone that can be cut out of a cube of edge 14 cm.</p>
<p>ABCD is cyclic quadrilateral and O is the center of the circle. If COD = 140<sup>o</sup> and BAC= 40<sup>o</sup>, then the value of BCD is equal to-</p>
<p>Two circle C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If BDC = 120<sup>o</sup>, then the value of ABP is equal to -</p>