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1. |
Find the point at which the tangent to the curve y= ( sqrt{4x^2+1} )-2 has its slope2. |
A. | ( ( frac{1}{ sqrt{12}} ),-1) and ( ( frac{1}{ sqrt{12}} ),-1) |
B. | (- ( frac{1}{ sqrt{12}} ),3) and (- ( frac{1}{ sqrt{12}} ),-1) |
C. | ( ( frac{1}{ sqrt{12}} ),2) and (- ( frac{1}{ sqrt{12}} ),-2) |
D. | ( ( frac{1}{ sqrt{12}} ),3) and ( ( frac{1}{ sqrt{12}} ),-2) |
Answer» D. ( ( frac{1}{ sqrt{12}} ),3) and ( ( frac{1}{ sqrt{12}} ),-2) | |