 
			 
			MCQOPTIONS
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				| 1. | Find the error voltage of phase comparator whose input signal is Vs= Vssin(2πfst) and the output signal Vo= Vosin(2πfot+φ).$ | 
| A. | V<sub>e</sub>=[k×(V<sub>s</sub>/2)]×[cos(-φ)-cos(2πf<sub>o</sub>t+φ)]. | 
| B. | V<sub>e</sub>=[k×V<sub>s</sub>×(V<sub>o</sub>/2)]×[cos(-φ)-cos(2πf<sub>o</sub>t+φ)]. | 
| C. | V<sub>e</sub>=[k×V<sub>s</sub>×(V<sub>o</sub>/2)]×[cos(-φ)+cos(2πf<sub>o</sub>t+φ)]. | 
| D. | V<sub>e</sub>=[k×V<sub>s</sub>×V<sub>o</sub>]×[cos(-φ)-cos(2πf<sub>o</sub>t+φ)]. | 
| Answer» C. V<sub>e</sub>=[k‚Äö√†√∂‚àö‚â•V<sub>s</sub>‚Äö√†√∂‚àö‚â•(V<sub>o</sub>/2)]‚Äö√†√∂‚àö‚â•[cos(-‚âà√¨‚àö√∫)+cos(2‚âà√¨‚àö√ëf<sub>o</sub>t+‚âà√¨‚àö√∫)]. | |