Find relation between a and b such that the following limit is got after a single application of L hospitals Rule \(lt_{x\rightarrow 0}\frac{ae^x+be^{2x}}{be^x+ae^{2x}}\)

Find relation between a and b such that the following limit is got af

1.	Find relation between a and b such that the following limit is got after a single application of L hospitals Rule \(lt_{x\rightarrow 0}\frac{ae^x+be^{2x}}{be^x+ae^{2x}}\)
A.	b⁄a = 2
B.	a⁄b = 2
C.	a = b
D.	a = -b
Answer» E.

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