Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e^{3x})}\)

Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e

1.	Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e^{3x})}\)
A.	3⁄2
B.	0
C.	4⁄3
D.	–4⁄3
Answer» D. –4⁄3

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Find \(lt_{x\rightarrow 0}\frac{(3e^x-2e^{2x}-e^{3x})}{(e^x+e^{2x}-2e^{3x})}\)