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1. |
Euler’s Bucking load on a column of length ‘I’ with both hinged, is given as(E = Young’s Modulus; I = Moment of Inertia of Column Cross-section) |
A. | \(\frac{2\pi EI}{L^2}\) |
B. | \(3\frac{\pi^2 EI}{L^2}\) |
C. | \(\frac{\pi^2 EI}{L^2}\) |
D. | \(\frac{2\pi^2 EI}{L^2}\) |
Answer» D. \(\frac{2\pi^2 EI}{L^2}\) | |