Electric potential varies with distance such that V(x) =ax-bx3; where a and b are constants. Where will the electric field intensity be zero?

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

x=  (  frac {a}{b}  )

TuteeHUB · Answer

x=  (  frac {a}{3b}  )

TuteeHUB · Answer

x=  (  sqrt{  frac {a}{b}}  )

TuteeHUB · Answer

x=+  (  sqrt{  frac {a}{3b}}  ) and x=-  (  sqrt{  frac {a}{3b}}  )

1.	Electric potential varies with distance such that V(x) =ax-bx³; where a and b are constants. Where will the electric field intensity be zero?
A.	x= ( frac {a}{b} )
B.	x= ( frac {a}{3b} )
C.	x= ( sqrt{ frac {a}{b}} )
D.	x=+ ( sqrt{ frac {a}{3b}} ) and x=- ( sqrt{ frac {a}{3b}} )
Answer» E.

Electric potential varies with distance such that V(x) =ax-bx³; where a and b are constants. Where will the electric field intensity be zero?