Division of (131B6C3) base 16 by (lA2F) base 16 yeilds ‚Äö√Ñ√ – McqOptions

MCQOPTIONS

1.	Division of (131B6C3) base 16 by (lA2F) base 16 yeilds ‚Äö√Ñ√∂‚àö√ë‚àö¬?#
A.	1AD
B.	DAD
C.	BAD
D.	9AD
Answer» E.

Discussion

No Comment Found

Related MCQs

Reduce the following big-O natations:
The estimated computations required to crack a password of 6 characters from the 26 letter alphabet is-
An encryption scheme is unconditionally secure if the ciphertext generated does not contain enough information to determine uniquely the corresponding plaintext, no matter how much cipher text is available.
Division of (131B6C3) base 16 by (lA2F) base 16 yeilds –
In base 26, multiplication of YES by NO gives –
Dividing (11001001) by (100111) gives remainder –
Divide (HAPPY)26 by (SAD)26. We get quotient –
AN_ENCRYPTION_SCHEME_IS_UNCONDITIONALLY_SECURE_IF_THE_CIPHERTEXT_GENERATED_DOES_NOT_CONTAIN_ENOUGH_INFORMATION_TO_DETERMINE_UNIQUELY_THE_CORRESPONDING_PLAINTEXT,_NO_MATTER_HOW_MUCH_CIPHER_TEXT_IS_AVAILABLE.?$
The_estimated_computations_required_to_crack_a_password_of_6_characters_from_the_26_letter_alphabet_is-$
Division of (131B6C3) base 16 by (lA2F) base 16 yeilds ‚Äö√Ñ√∂‚àö√ë‚àö¬?#