Dilation on parallelepiped with strains in x, y, z direction equals to – McqOptions

MCQOPTIONS

1.	Dilation on parallelepiped with strains in x, y, z direction equals to x, y, z respectively: The total volume change is given as = x + y + z for the small strain. The mean stress or hydrostatic (spherical) component of stress will be equal to ____
A.
B.	/2
C.	/3
D.	/4
Answer» D. /4

Discussion

No Comment Found

Related MCQs

What does <sub>ij</sub> represent in a 3 3 stress matrix?
Calculate the dilation of body, given that the initial volume is 250 mm<sup>2</sup> and final volume is 235.5 mm<sup>2</sup>.
Calculate the hydrostatic strain, if x, y, z are 0.01, 0.2, 0.05 respectively?
Experimentally, strain in the material with high precision is measured by _________ method.
The part of strain tensor which involves in the shape change rather than the volume change is called strain deviator ij.
Dilation on parallelepiped with strains in x, y, z direction equals to x, y, z respectively:<br>The total volume change is given as = x + y + z for the small strain. The mean stress or hydrostatic (spherical) component of stress will be equal to ____
Dilation of the mechanical body is ____________
For the following stress matrix, the first invariant of the stress tensor is the trace of a matrix, the sum of diagonal element: I<sub>1</sub> = <sub>11</sub> + <sub>22</sub> + <sub>33</sub>. The second invariant of matrix is equal to _________<br> ( begin{vmatrix} sigma_{11} & sigma_{12} & sigma_{13} sigma_{21}& sigma_{22} & sigma_{23} sigma_{31}& sigma_{32} & sigma_{33} end{vmatrix} )
The number of components required to define an elastic constant is ______
Matrix (2-dimensional arrays) is a second rank tensor.