1.

\[\Delta ABC,\] if \[\cos \frac{A}{2}=\sqrt{\frac{b+c}{2c}}\], then [MP PET 1990]

A. \[{{a}^{2}}+{{b}^{2}}={{c}^{2}}\]
B. \[{{b}^{2}}+{{c}^{2}}={{a}^{2}}\]
C. \[{{c}^{2}}+{{a}^{2}}={{b}^{2}}\]
D. \[b-c=c-a\]
Answer» B. \[{{b}^{2}}+{{c}^{2}}={{a}^{2}}\]


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