Compound ?A? (molecular formula \[{{C}_{3}}{{H}_{8}}O)\] is treated with acidified potassium dichromate to form a product ?B? (molecular formula \[{{C}_{3}}{{H}_{6}}O).\] ?B? forms a shining silver mirror on warming with ammoniacal silver nitrate. ?B? when treated with an aqueous solution of \[{{H}_{2}}NCONHN{{H}_{2}}.HCl\] and sodium acetate gives a product ?C?. Identify the structure of ?C? [IIT-JEE (Screening) 2002]

• A. \[C{{H}_{3}}C{{H}_{2}}CH=NNHCON{{H}_{2}}\]
• B. \[C{{H}_{3}}-CH=\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,}{\mathop{NNH}}\,}}\,CON{{H}_{2}}\]
• C. \[C{{H}_{3}}CH=\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,}{\mathop{NCO}}\,}}\,NHN{{H}_{2}}\]
• D. \[C{{H}_{3}}C{{H}_{2}}CH-NCONHN{{H}_{2}}\]