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1. |
Calculate the carbon carbon double bond energy in ethane from the following reaction, H2C=CH2(g) + H2(g) > H3C CH3(g) H = 138 kJ/mol. If Bond enthalpies are: C C = 348; H H = 436; C H = 412 in KJ/mol. |
A. | 498 KJ/mol |
B. | 593 KJ/mol |
C. | 508 KJ/mol |
D. | 598 KJ/mol |
Answer» E. | |