By combining ( Delta= frac{R}{2^{b+1}} ) with (P_n= sigma_e^2= Delta^2/12 ) and substituting the result into SQNR = 10 (log_{10} frac{P_x}{P_n} ), what is the final expression for SQNR = ?

Question

By combining  ( Delta= frac{R}{2^{b+1}} ) with  (P_n= sigma_e^2= Delta^2/12 ) and substituting the result into SQNR = 10  (log_{10}   frac{P_x}{P_n} ), what is the final expression for SQNR = ?

TuteeHUB · Accepted Answer

6.02b   16.81     (20log_{10} u2061   frac{R}{ _x}  )

TuteeHUB · Answer

6.02b + 16.81 +   (20log_{10}  frac{R}{ _x}  )

TuteeHUB · Answer

6.02b + 16.81     (20log_{10} u2061   frac{R}{ _x}  )

TuteeHUB · Answer

6.02b   16.81     (20log_{10} u2061   frac{R}{ _x}  )

TuteeHUB · Answer

6.02b   16.81     (20log_{10} u2061   frac{R}{ _x}  )

1.	By combining ( Delta= frac{R}{2^{b+1}} ) with (P_n= sigma_e^2= Delta^2/12 ) and substituting the result into SQNR = 10 (log_{10} frac{P_x}{P_n} ), what is the final expression for SQNR = ?
A.	6.02b + 16.81 + (20log_{10} frac{R}{ _x} )
B.	6.02b + 16.81 (20log_{10} u2061 frac{R}{ _x} )
C.	6.02b 16.81 (20log_{10} u2061 frac{R}{ _x} )
D.	6.02b 16.81 (20log_{10} u2061 frac{R}{ _x} )
Answer» C. 6.02b 16.81 (20log_{10} u2061 frac{R}{ _x} )

By combining ( Delta= frac{R}{2^{b+1}} ) with (P_n= sigma_e^2= Delta^2/12 ) and substituting the result into SQNR = 10 (log_{10} frac{P_x}{P_n} ), what is the final expression for SQNR = ?

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