At a place the value of horizontal component of the earth's magnetic field H is $$3\times {{10}^{-5}}\,Weber/{{m}^{2}}$$. A metallic rod AB of length 2 m placed in east-west direction, having the end A towards east, falls vertically downward with a constant velocity of 50 m/s. Which end of the rod becomes positively charged and what is the value of induced potential difference between the two ends [MP PET 1996]

Question

At a place the value of horizontal component of the earth's magnetic field H is $$3\times {{10}^{-5}}\,Weber/{{m}^{2}}$$. A metallic rod AB of length 2 m placed in east-west direction, having the end A towards east, falls vertically downward with a constant velocity of 50 m/s. Which end of the rod becomes positively charged and what is the value of induced potential difference between the two ends  [MP PET 1996]

TuteeHUB · Accepted Answer

$$9\times {{10}^{-9}}$$

TuteeHUB · Answer

End A, $$3\times {{10}^{-3}}\,mV$$

TuteeHUB · Answer

End A, 3 mV

TuteeHUB · Answer

$$9\times {{10}^{-9}}$$

TuteeHUB · Answer

End B, 3 mV

1.	At a place the value of horizontal component of the earth's magnetic field H is \[3\times {{10}^{-5}}\,Weber/{{m}^{2}}\]. A metallic rod AB of length 2 m placed in east-west direction, having the end A towards east, falls vertically downward with a constant velocity of 50 m/s. Which end of the rod becomes positively charged and what is the value of induced potential difference between the two ends [MP PET 1996]
A.	End A, \[3\times {{10}^{-3}}\,mV\]
B.	End A, 3 mV
C.	\[9\times {{10}^{-9}}\]
D.	End B, 3 mV
Answer» C. \[9\times {{10}^{-9}}\]

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