1.

Arrhenius equation to determine the activation energy.

A. ln⁡\((\frac{k1}{k2}) = \frac{E}{R} (\frac{1}{T2}-\frac{1}{T1}) \)
B. ln⁡\((\frac{k1}{k2}) = \frac{E}{R} (\frac{1}{T2}+\frac{1}{T1}) \)
C. ln⁡\((\frac{k1}{k2}) = -\frac{E}{R} (\frac{1}{T2}-\frac{1}{T1}) \)
D. ln⁡\((\frac{k1}{k2}) = \frac{E}{R} (\frac{T1}{T2}) \)
Answer» B. ln⁡\((\frac{k1}{k2}) = \frac{E}{R} (\frac{1}{T2}+\frac{1}{T1}) \)


Discussion

No Comment Found