1.

An alternating voltage of 360 V, 50 Hz is applied to a full-wave rectifier. The internal resistance of each diode is 100 W. If RL = 5 kW, then what is the peak value of output current?

A. 0.9 A
B. 0.07 A
C. 0.097 A
D. 1.097 A
Answer» D. 1.097 A


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