1.

According to fuse law, the current carrying capacity varies as

A. diameter
B. (diameter)1.5
C. \({\left( {{\rm{diameter}}} \right)^{\frac{1}{2}}}\)
D. \(\frac{1}{{diameter}}\)
Answer» C. \({\left( {{\rm{diameter}}} \right)^{\frac{1}{2}}}\)


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