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1. |
According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2 where m is equal to |
A. | .405 + (0.003/H) |
B. | .003 + (0.405/H) |
C. | .405 + (H/0.003) |
D. | .003 + (H/0.405) |
Answer» B. .003 + (0.405/H) | |