1.

According to Bazin's formula, the discharge over a rectangular weir is mL2g x H3/2 where m is equal to

A. .405 + (0.003/H)
B. .003 + (0.405/H)
C. .405 + (H/0.003)
D. .003 + (H/0.405)
Answer» B. .003 + (0.405/H)


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