A voltage of 50 sin 1000 t V is applied across a parallel plate capacitor with plate area of 5 cm2 and plate separation gap of 5 mm. If the dielectric material the capacitor has ε = 2 ε0, then the capacitor current will be (in amperes)

\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\sin {10^3}t\)

\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\cos {10^3}t\)

\({\varepsilon _0}{10^4}\cos {10^3}t\)

\({\varepsilon _0}{10^4}\sin {10^3}t\)

A voltage of 50 sin 1000 t V is applied across a parallel plate capaci

1.	A voltage of 50 sin 1000 t V is applied across a parallel plate capacitor with plate area of 5 cm2 and plate separation gap of 5 mm. If the dielectric material the capacitor has ε = 2 ε0, then the capacitor current will be (in amperes)
A.	\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\cos {10^3}t\)
B.	\({\varepsilon _0}{10^4}\cos {10^3}t\)
C.	\(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\sin {10^3}t\)
D.	\({\varepsilon _0}{10^4}\sin {10^3}t\)
Answer» C. \(\frac{{{{10}^4}}}{{{\varepsilon _0}}}\sin {10^3}t\)

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A voltage of 50 sin 1000 t V is applied across a parallel plate capacitor with plate area of 5 cm2 and plate separation gap of 5 mm. If the dielectric material the capacitor has ε = 2 ε0, then the capacitor current will be (in amperes)

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