1.

A tube of uniform cross section always has water flowing through it. It is kept vertical in such a way that water enters from top and leaves from the bottom. If the speed at a point A below the opening is ‘v’, what will be the speed at a point B vertically below A such that the distance between A & B is ‘2h’?

A. v
B. \(\sqrt{v^2 + 4gh}\)
C. \(\sqrt{v^2 + 2gh}\)
D. v/2
Answer» B. \(\sqrt{v^2 + 4gh}\)


Discussion

No Comment Found