

MCQOPTIONS
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1. |
A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of [IIT-JEE (Screening) 1999] |
A. | \[(2/3)k\] |
B. | \[(3/2)k\] |
C. | For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats |
D. | \[6k\] |
Answer» C. For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats | |