1.

A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of [IIT-JEE (Screening) 1999]

A. \[(2/3)k\]
B. \[(3/2)k\]
C. For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats
D. \[6k\]
Answer» C. For an adiabatic change \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\], where \[\gamma \] is the ratio of specific heats


Discussion

No Comment Found

Related MCQs