A shaft of diameter (d) subject to a bending moment (M) and a twisting moment (T) at a section. The maximum shear stress is given by the equation

\({\tau _{max}} = \frac{{16}}{{{d^3}}}\sqrt {{M^2} + {T^2}} \)

\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {{M^2} + {T^2}} \)

\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {1 + {T^2}} \)

\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {{M^2} + 1} \)

A shaft of diameter (d) subject to a bending moment (M) and a twisting

1.	A shaft of diameter (d) subject to a bending moment (M) and a twisting moment (T) at a section. The maximum shear stress is given by the equation
A.	\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {{M^2} + {T^2}} \)
B.	\({\tau _{max}} = \frac{{16}}{{{d^3}}}\sqrt {{M^2} + {T^2}} \)
C.	\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {1 + {T^2}} \)
D.	\({\tau _{max}} = \frac{{16}}{{\pi {d^3}}}\sqrt {{M^2} + 1} \)
Answer» B. \({\tau _{max}} = \frac{{16}}{{{d^3}}}\sqrt {{M^2} + {T^2}} \)

Discussion

No Comment Found

Related MCQs

Maximum shear stress developed on the surface of a solid circular shaft under pure torsion is 160 MPa. If the shaft diameter is doubled, then the maximum shear stress developed corresponding to the same torque will be:
A circular shaft subjected to torsion undergoes a twist of 1° in a length of 120 cm. if the maximum shear stress induced is limited to 1000 kg/cm2 and of modulus of rigidity G= 0.8 × 106 kg/cm2, then the radius of the shaft should be
A solid circular shaft is to transmit power, P kW when turning N revolutions per min. For a given maximum shear stress, the shaft diameter will be proportional to
A solid circular shaft of 20 mm diameter transmits a torque of 1570 Nm. The value of maximum shear stress developed is nearly
A hollow shaft of 20 mm diameter and 16 mm inside diameter is subjected to a torque of 40 Nm. The shear stress at outside of the shaft will be:
A shaft is subjected to a bending moment M = 0.75 kN-m and a twisting moment T = 1 kN-m. The magnitude of equivalent bending moment in shaft is
A member is subjected to the combined action of bending 400 N-m and torque 300 N-m. What are the equivalent bending moment and equivalent torque respectively?
A solid circular shaft is subjected to a bending moment M and torque T simultaneously. Neglecting the effects to stress concentration, the equivalent bending moment is expressed as
In the torsion equation \(\frac{T}{J} = \frac{τ }{r} = \frac{{Cθ }}{L}\). The term \(\frac{J}{r}\) is called
A rigid horizontal rod of length 2L is fixed to a circular cylinder of radius R as shown in the figure. Vertical forces of magnitude P are applied at the two ends as shown in the figure. The shear modulus for the cylinder is G and the Young’s modulus is E.The vertical deflection at point A is

A shaft of diameter (d) subject to a bending moment (M) and a twisting moment (T) at a section. The maximum shear stress is given by the equation

Discussion

No Comment Found

Related MCQs

Reply to Comment