1.

A series R-L circuit (R = 4 Ω and L = 0.01 H) is excited by a voltage (in volt) v(t) = 283 sin (300t + 90°). The current in the circuit will be

A. 40 sin ( 300t + 53.1°) A
B. 40 sin ( 53.1°) A
C. 40√2 sin ( 300t + 53.1°) A
D. 40√2 sin ( 53.1°) A
Answer» D. 40√2 sin ( 53.1°) A


Discussion

No Comment Found

Related MCQs