A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t2 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?

A particle moves in a straight line and its velocity v at time t secon

1.	A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t² 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?
A.	10cm/sec<sup>2</sup>
B.	12cm/sec<sup>2</sup>
C.	14cm/sec<sup>2</sup>
D.	16cm/sec<sup>2</sup>
Answer» D. 16cm/sec<sup>2</sup>

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A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t2 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?

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A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t² 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?