A particle moves along the x-axis according to the law ( frac{d^2 x}{dt^2} + 6 frac{dx}{dt} + 25x = 0. ) If the particle is started at x=0 with an initial velocity of 12ft/sec to the left, determine x in terms of t.

Question

A particle moves along the x-axis according to the law  ( frac{d^2 x}{dt^2} + 6  frac{dx}{dt} + 25x = 0. ) If the particle is started at x=0 with an initial velocity of 12ft/sec to the left, determine x in terms of t.

TuteeHUB · Accepted Answer

x=-e^-3t (sin u20614t+cos 4t)

TuteeHUB · Answer

x=-3e-3t sin u20614t

TuteeHUB · Answer

x=-e-3t (sin u20614t+cos 4t)

TuteeHUB · Answer

x=-3e-3t (sin u20614t+cos u20614t)

TuteeHUB · Answer

x=-3e-3t cos u20614t

1.	A particle moves along the x-axis according to the law ( frac{d^2 x}{dt^2} + 6 frac{dx}{dt} + 25x = 0. ) If the particle is started at x=0 with an initial velocity of 12ft/sec to the left, determine x in terms of t.
A.	x=-3e<sup>-3t</sup> sin u20614t
B.	x=-e<sup>-3t</sup> (sin u20614t+cos 4t)
C.	x=-3e<sup>-3t</sup> (sin u20614t+cos u20614t)
D.	x=-3e<sup>-3t</sup> cos u20614t
Answer» B. x=-e<sup>-3t</sup> (sin u20614t+cos 4t)

A particle moves along the x-axis according to the law ( frac{d^2 x}{dt^2} + 6 frac{dx}{dt} + 25x = 0. ) If the particle is started at x=0 with an initial velocity of 12ft/sec to the left, determine x in terms of t.

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