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This section includes 7 Mcqs, each offering curated multiple-choice questions to sharpen your Ordinary Differential Equations knowledge and support exam preparation. Choose a topic below to get started.
1. |
The solution of differential equation \(\frac{dy}{dx} = \frac{y}{x} + tan\frac{y}{x}\) is ______ |
A. | \(cot(\frac{y}{x}) = xc\) |
B. | \(cos(\frac{y}{x}) = xc\) |
C. | \(sec^2(\frac{y}{x}) = xc\) |
D. | \(sin(\frac{y}{x}) = xc\) |
Answer» E. | |
2. |
Solve the differential equation \(\frac{dy}{dx} = \frac{x^2+y^2}{3xy}\) is _______ |
A. | xp=(x2+2y2)-3 |
B. | x2 p=(x2-2y2)3 |
C. | x4 p=(x2-2y2)-3 |
D. | x6 p=(x2+2y2)3 |
Answer» C. x4 p=(x2-2y2)-3 | |
3. |
Solution of the differential equation \(xy \frac{dy}{dx} = 1+x+y+xy\) is ______ |
A. | (y-x)-log(x(1+y))=c |
B. | log(x(1+y))=c |
C. | (y+x)-log(x)=c |
D. | (y-x)-log(y(1+x))=c |
Answer» B. log(x(1+y))=c | |
4. |
Solution of the differential equation \(\frac{dy}{dx} = (4x+2y+1)^2\) is ______ |
A. | \(\frac{1}{2\sqrt{2}} tan^{-1}(\frac{4x+2y+1}{\sqrt{2}})=x+c \) |
B. | \(\frac{1}{\sqrt{2}} cot^{-1}(4x+2y+1)=x+c \) |
C. | \(\frac{1}{\sqrt{2}} tan^{-1}(\frac{4x+2y+1}{\sqrt{2}})=c \) |
D. | cot-1(4x+2y+1)=x+c |
Answer» B. \(\frac{1}{\sqrt{2}} cot^{-1}(4x+2y+1)=x+c \) | |
5. |
Solution of the differential equation sec2 x tany dx + sec2 y tanx dy=0 is _______ |
A. | (sec x. sec y)=k |
B. | (sec x .tany)=k |
C. | (tan x. tany)=k |
D. | (sec x .tan x)+(sec y .tan y)=k |
Answer» D. (sec x .tan x)+(sec y .tan y)=k | |
6. |
Solution of the differential equation \(\frac{dy}{dx} = e^{3x-2y} + x^2 e^{-2y}\) is ______ |
A. | \( \frac{e^{2y}}{3} = \frac{e^{3x}}{3} + \frac{x^2}{2} + c\) |
B. | \( \frac{e^{3y} (e^{2x}+x^3)}{6} + c\) |
C. | \(\frac{e^{2y} (e^{3x}+x^3)}{6} + c\) |
D. | \( \frac{e^{2y}}{2} = \frac{e^{3x}}{3} + \frac{x^3}{3} + c\) |
Answer» E. | |
7. |
Solution of the differential equation \(\frac{dy}{dx} = \frac{y(x-y lny)}{x(x ln x-y)}\) is _____________ |
A. | \(\frac{x lnx+y lny}{xy} = c\) |
B. | \(\frac{x lnx-y lny}{xy} = c\) |
C. | \(\frac{lnx}{x} + \frac{lny}{y} = c\) |
D. | \(\frac{lnx}{x} – \frac{lny}{y} = c\) |
Answer» B. \(\frac{x lnx-y lny}{xy} = c\) | |