A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t 15t2 + 4t3. What is the acceleration of the particle after 3 seconds?

A particle is moving in a straight line and its distance s cm from a f

1.	A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t 15t² + 4t³. What is the acceleration of the particle after 3 seconds?
A.	41 cm/sec<sup>2</sup>
B.	42 cm/sec<sup>2</sup>
C.	43 cm/sec<sup>2</sup>
D.	44 cm/sec<sup>2</sup>
Answer» C. 43 cm/sec<sup>2</sup>

Discussion

No Comment Found

Related MCQs

A particle starts moving from rest with an acceleration in a fixed direction. If its acceleration at time t be(a bt2),where a and b are positive constants then which one is correct?
Two straight railway lines meet at right angles. A train starts from the junction along one line and at the same time instant, another train starts towards the junction from a station on the other line and they move at the same uniform velocity.When will they be nearest to each other?
The distance x of a particle moving along a straight line from a fixed point on the line at time t after start is given by t = ax2 + bx + c (a, b, c are positive constants). If v be the velocity of the particle at the instant, then which one is correct?
A particle moves along the straight-line OX, starting from O with a velocity 4 cm/sec. At time t seconds its acceleration is (5 + 6t) cm/sec2. What will be the distance from O after 4 seconds?
A particle moves along the straight-line OX, starting from O with a velocity 4 cm/sec. At time t seconds its acceleration is (5 + 6t) cm/sec2. What will be the velocity of the particle from O after 4 seconds?
A particle moves in a straight line and its velocity v at time t seconds is given byv = 3t2 4t + 5 cm/second. What will be the acceleration of the particle during first 3 seconds after the start?
A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct2 (a, b > 0). What will be the nature of motion of the particle when c < 0?
A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct2 (a, b > 0). What will be the nature of motion of the particle when c > 0?
A particle moves in a straight-line OA; the distance of the particle from O at time t seconds is x ft, where x = a + bt + ct2 (a, b > 0). What is the meaning of the constant c?
A particle is moving along the straight line OX and its distance x is in metres from O after t seconds from start is given by x = t3 t2 5t. What will be the acceleration of the particle when it is at a distance 28 metres from O?

A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t 15t2 + 4t3. What is the acceleration of the particle after 3 seconds?

Discussion

No Comment Found

Related MCQs

Reply to Comment

A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t 15t² + 4t³. What is the acceleration of the particle after 3 seconds?