A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is [Kerala PET 2005]

The energy associated with the resulting motion is \[(3+2\sqrt{2)}\] times the energy associated with any single motion

A particle executes linear simple harmonic motion with an amplitude of

1.	A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is [Kerala PET 2005]
A.	\[\frac{1}{2\pi \sqrt{3}}\]
B.	\[2\pi \sqrt{3}\]
C.	The energy associated with the resulting motion is \[(3+2\sqrt{2)}\] times the energy associated with any single motion
D.	\[\frac{\sqrt{3}}{2\pi }\]
Answer» D. \[\frac{\sqrt{3}}{2\pi }\]

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A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is [Kerala PET 2005]

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