A man of height 6 feet walks at uniform rate of 3kmph away from the lamp post of 15 feet height. The rate at which the length of his shadow changes is

A man of height 6 feet walks at uniform rate of 3kmph away from the la

1.	A man of height 6 feet walks at uniform rate of 3kmph away from the lamp post of 15 feet height. The rate at which the length of his shadow changes is
A.	2 kmph, decreases
B.	2 kmph increases
C.	4.5 kmph, increases
D.	4.5 kmph decreases
Answer» C. 4.5 kmph, increases

Discussion

No Comment Found

Related MCQs

If \({\rm{y}} = {\sec ^{ - 1}}\left( {\frac{{{\rm{x}} + 1}}{{{\rm{x}} - 1}}} \right) + {\sin ^{ - 1}}\left( {\frac{{{\rm{x}} - 1}}{{{\rm{x}} + 1}}} \right)\), then \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) is equal to
Let \({\rm{f}}\left( {{\rm{x}},{\rm{y}}} \right) = \frac{{{\rm{a}}{{\rm{x}}^2} + {\rm{b}}{{\rm{y}}^2}}}{{{\rm{xy}}}}\), where a and b are constants. If \(\frac{{\partial {\rm{f}}}}{{\partial {\rm{x}}}} = \frac{{\partial {\rm{f}}}}{{\partial {\rm{y}}}}{\rm{\;}}\) at x = 1 and y = 2, then the relation between a and b is
If \(f\left( x \right) = \frac{{{x^3}}}{3} - \frac{{5{x^2}}}{2} + 6x + 7\) increases in the interval T and decreases in the interval S, then which one of the following is correct?
Find the differentiation of \({\cos ^{ - 1}}x\)
If v = yz î + 3zx ĵ + z k̂, then curl v is
Change the order of integration in\(\mathop{\int }_{0}^{a}\mathop{\int }_{y}^{a}\frac{x}{{{x}^{2}}+{{y}^{2}}}dx~dy\)
Each of four particles move along an x-axis. Their coordinates (in meters) as functions of time (in seconds) are given by1) particle 1: x (t) = 3.5 – 2.7 t32) particle 2: x (t) = 3.5 + 2.7 t33) particle 3: x (t) = 3.5 – 2.7 t24) particle 4: x (t) = 3.5 – 3.4t - 2.7 t2Which of these particles have constant acceleration?
Differentiate {-log (log x), x > 1} with respect to x
A function f(x) = 1 - x2 + x3 is defined in the closed interval [-1, 1]. The value of x, in the open interval (-1, 1) for which the mean value theorem is satisfied, is
If \(u = \log \left( {\frac{{{x^2} + {y^2}}}{{x + y}}} \right)\) then \(x\frac{{\partial u}}{{\partial x}} + y\frac{{\partial u}}{{\partial x}}\) is equal to –

A man of height 6 feet walks at uniform rate of 3kmph away from the lamp post of 15 feet height. The rate at which the length of his shadow changes is

Discussion

No Comment Found

Related MCQs

Reply to Comment