A curve passes through (1, 1) such that the triangle formed by the coordinate axes and the tangent at any point of the curve is in the first quadrant and has its area equal to 2. What is the differential equation?

dy/dx = [(xy + 2) (1 + xy)]/ x2

A curve passes through (1, 1) such that the triangle formed by the coo

1.	A curve passes through (1, 1) such that the triangle formed by the coordinate axes and the tangent at any point of the curve is in the first quadrant and has its area equal to 2. What is the differential equation?
A.	dy/dx = [(xy + 2) (1 + xy)]/ x<sup>2</sup>
B.	dy/dx = [(xy 2) (1 + xy)]/ x<sup>2</sup>
C.	dy/dx = [(xy 2) (1 xy)]/ x<sup>2</sup>
D.	dy/dx = [(xy + 2) (1 xy)]/ x<sup>2</sup>
Answer» D. dy/dx = [(xy + 2) (1 xy)]/ x<sup>2</sup>

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