1.

A circular shaft of diameter 30 mm is tested under torsion the gauge length of test specimen is 300 mm. A torque of 2kNm produces an angle twist of 1°. Calculate CJ.

A. 0.432 √ó 10<sup>6</sup> N/mm<sup>2</sup>
B. 0.324 √ó 10<sup>6</sup> N/mm<sup>2</sup>
C. 0.46 √ó 10<sup>6</sup> N/mm<sup>2</sup>
D. 0.532 √ó 10<sup>6</sup> N/mm<sup>2</sup>
Answer» B. 0.324 ‚Äö√†√∂‚àö‚â• 10<sup>6</sup> N/mm<sup>2</sup>


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