A circular cavity resonator has a wave number of 151, radius of 2.74 cm, and surface resistance of 0.0184Ω. If the cavity is filled with a dielectric of 2.01, then unloaded Q due to conductor loss is:

A circular cavity resonator has a wave number of 151, radius of 2.74

1.	A circular cavity resonator has a wave number of 151, radius of 2.74 cm, and surface resistance of 0.0184Ω. If the cavity is filled with a dielectric of 2.01, then unloaded Q due to conductor loss is:
A.	25490
B.	21460
C.	29390
D.	none of the mentioned
Answer» D. none of the mentioned

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A_CIRCULAR_CAVITY_RESONATOR_HAS_A_WAVE_NUMBER_OF_151,_RADIUS_OF_2.74_CM,_AND_SURFACE_RESISTANCE_OF_0.0184‚ÂÀ√≠¬¨¬©._IF_THE_CAVITY_IS_FILLED_WITH_A_DIELECTRIC_OF_2.01,_THEN_UNLOADED_Q_DUE_TO_CONDUCTOR_LOSS_IS:?$#
If unloaded Q due to conductor loss and unloaded Q due to dielectric loss is 29390 and 2500 respectively, then the total unloaded Q of the circular cavity is:$
The loss tangent for a circular cavity resonator is 0.0004.Then the unloaded Q due to dielectric loss is?
Given that the wave number of a circular cavity resonator is 151 (TE011 mode), and the length of the cavity is twice the radius of the cavity, the radius of the circular cavity operating at 5GHz frequency is:

A circular cavity resonator has a wave number of 151, radius of 2.74 cm, and surface resistance of 0.0184Ω. If the cavity is filled with a dielectric of 2.01, then unloaded Q due to conductor loss is:

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