A 100 MW power station delivers 100 MW for 2 hours, 50 MW for 6 hours – McqOptions

MCQOPTIONS

1.	A 100 MW power station delivers 100 MW for 2 hours, 50 MW for 6 hours in a day and is shut down for maintenance for 45 days each year. Calculate its annual load factor?
A.	20%
B.	21%
C.	22.5%
D.	18.3%
Answer» E.

Discussion

No Comment Found

Related MCQs

Incremental fuel costs in Rs/MWh for a plant consisting of two generating units are given by\(\frac{{d{F_1}}}{{d{P_1}}} = 0.4{P_1} + 400\;and\frac{{d{F_2}}}{{d{P_2}}} = 0.48{P_2} + 320\)The allocation of loads P1 and P2 between generating units 1 and 2, respectively, for minimum cost of generation to serve a total load of 900 MW, neglecting losses, is
A generating station has a maximum demand of 500 MW. The annual load factor is 50 percent. The energy generated per annum will be:
If the fuel cost of one unit, operating in parallel with other units, is increased and it is desired to maintain fuel cost, the load on the unit will be
A generating station has 500 MW maximum demand and annual load factor of 50%, capacity factor of 40%. The reserve capacity of the plant is
Maximum demand meter indicates
A power generating station has a maximum demand of 1000 MW. The annual load demand of 1000 MW. The annual load factor is 75% and plant capacity factor is 60%. Calculate the reserve capacity.
A consumer consumes 600 kWh per day at a load factor of 0.5. Without increasing the maximum demand, if the consumer increases the load factor to 0.8, the consumption of energy in kWh would be:
Plant capacity factor of a power plant may be calculated by the formula:
Base load power plants areP. wind farmsQ. run – of – river plantsR. nuclear power plantsS. diesel power plants
Demand factor of a power plant is: