1.5 g of enzyme gives a vmax of 3 mol product produced per minute. What is the turnover number for this enzyme?

1.5 g of enzyme gives a vmax of 3 mol product produced per minute. W

1.	1.5 g of enzyme gives a v_max of 3 mol product produced per minute. What is the turnover number for this enzyme?
A.	100 sec<sup>-1</sup>
B.	200 sec<sup>-1</sup>
C.	1000 sec<sup>-1</sup>
D.	2000 sec<sup>-1</sup>
Answer» D. 2000 sec<sup>-1</sup>