WHAT_IS_THE_FORMULA_TO_CALCULATE_MAXIMUM_EFFICIENCY_OF_A_WORM_GEAR??$

(tan(‚âà√≠¬¨‚Ñ¢1-‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢1

(1+sin‚Äö√†√∂‚Äö√†√®)/(1-sin‚Äö√†√∂‚Äö√†√®)

(1-sin‚Äö√†√∂‚Äö√†√®)/(1+sin‚Äö√†√∂‚Äö√†√®)

(tan(‚âà√≠¬¨‚Ñ¢1-‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢1

(tan(‚âà√≠¬¨‚Ñ¢1+‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢1

Find_the_helix_angle_of_the_worm_if_the_pitch_of_the_worm_gear_is_12_mm_and_the_pitch_diameter_is_50_mm.$

11.231¬¨¬®‚Äö√†√ª

8.687¬¨¬®‚Äö√†√ª

11.231¬¨¬®‚Äö√†√ª

9.212¬¨¬®‚Äö√†√ª

10.319¬¨¬®‚Äö√†√ª

The_axial_thrust_on_the_worm_(WA)_is_given_by$

WA = WT . tan ‚âà√¨‚àö√∫

WA = WT / tan ‚âà√¨‚àö√∫

WA = WT . tan ‚âà√≠¬¨‚Ñ¢

WA = WT / tan ‚âà√≠¬¨‚Ñ¢

Calculate the lead angle of the worm gear for maximum efficiency if ‚âà√≠‚Äö√†√® = 90¬¨¬®‚Äö√†√ª and the coefficient of friction is 0.05.$

46.43¬¨¬®‚Äö√†√ª

48.21¬¨¬®‚Äö√†√ª

42.23¬¨¬®‚Äö√†√ª

43.57¬¨¬®‚Äö√†√ª

46.43¬¨¬®‚Äö√†√ª

What is the centre distance for the worm gear?

(mn/2)(T1 cot‚âà√≠¬¨‚Ñ¢1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® T2)

(mn/2)(T2 cot‚âà√≠¬¨‚Ñ¢1 + T1)

(mn/2)(T2 cot‚âà√≠¬¨‚Ñ¢1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® T1)

(mn/2)(T1 cot‚âà√≠¬¨‚Ñ¢1 + T2)

The normal lead, in a worm having multiple start threads, is given b?

lN = l / cos ‚âà√≠¬¨‚Ñ¢

lN = l . cos ‚âà√≠¬¨‚Ñ¢

For a bevel gear having the pitch angle ‚âà√≠‚Äö√†√®, the ratio of formative number of teeth (TE) to actual number of teeth (T) is$

1/tan ‚âà√≠‚Äö√†√®

1/sin ‚âà√≠‚Äö√†√®

1/cos ‚âà√≠‚Äö√†√®

1/tan ‚âà√≠‚Äö√†√®

sin ‚âà√≠‚Äö√†√® cos ‚âà√≠‚Äö√†√®

If b denotes the face width and L denotes the cone distance, then the bevel factor is written as

1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® 2 b.L

1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® b / L

Is it possible to use worm gears in cranes for lifting purpose?

No self-locking and hence not possible

Possible up to a threshold load

Which is of these is an advantage of worm gear?

Has high power losses and low transmission efficiency

Used for reducing speed and increasing torque

The face angle of a bevel gear is equal to

pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® dedendum angle

pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® addendum angle

pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® dedendum angle

52 + Mcqs in Worm Gears in Machine Design Page 1 McqOptions

1.	Find the maximum efficiency if the lead angle is given to be 10° and the coefficient of friction is 0.07.
A.	79.82%
B.	72.23%
C.	76.29%
D.	70.72%
Answer» E.

Discussion

2.	Calculate the lead angle of the worm gear for maximum efficiency if θ = 90° and the coefficient of friction is 0.05.
A.	48.21°
B.	42.23°
C.	43.57°
D.	46.43°
Answer» D. 46.43°

Discussion

3.	For a two start worm gear having a pitch of 20 mm and a lead angle 12°, find the centre distance if the larger gear has 25 teeth.
A.	148.22 mm
B.	124.93 mm
C.	121.19 mm
D.	109.53 mm
Answer» E.

Discussion

4.	Find the speed of the gear if the worm is a three start worm rotating at 500 rpm. The gear has 20 teeth.
A.	125 rpm
B.	100 rpm
C.	75 rpm
D.	50 rpm
Answer» D. 50 rpm

Discussion

5.	Find the helix angle of the worm if the pitch of the worm gear is 12 mm and the pitch diameter is 50 mm.
A.	8.687°
B.	11.231°
C.	9.212°
D.	10.319°
Answer» B. 11.231°

Discussion

6.	What is the formula to calculate maximum efficiency of a worm gear?
A.	(1+sinø)/(1-sinø)
B.	(1-sinø)/(1+sinø)
C.	(tan(λ1-ø))/tan λ1
D.	(tan(λ1+ø))/tan λ1
Answer» C. (tan(λ1-ø))/tan λ1

Discussion

7.	When large gear reductions are needed _________ gears are used.
A.	helical
B.	spur
C.	worm
D.	bevel
Answer» D. bevel

Discussion

8.	If tangential force on worm is 1500N, then axial force on worm wheel will be?
A.	1500N
B.	3000N
C.	1500√2 N
D.	750N
Answer» B. 3000N

Discussion

9.	A pair of worm gear is written as 2/40/12/6. Calculate the root diameter of the worm wheel.
A.	186.22mm
B.	250.4mm
C.	225.6mm
D.	250.44mmView Answer
Answer» D. 250.44mmView Answer

Discussion

10.	A pair of worm gear is written as 2/40/12/6. Calculate the throat diameter of the worm wheel.
A.	220.5mm
B.	246.4mm
C.	190.44mm
D.	251.7mm
Answer» E.

Discussion

11.	A pair of worm gear is written as 2/40/12/6. Calculate the pitch circle diameter of worm wheel.
A.	72mm
B.	240mm
C.	260mm
D.	320mm
Answer» C. 260mm

Discussion

12.	A pair of worm gear is written as 2/40/12/6. Calculate the speed reduction.
A.	2
B.	20
C.	15
D.	6
Answer» C. 15

Discussion

13.	A pair of worm gear is written as 2/40/12/6. Calculate the centre distance.
A.	40mm
B.	156mm
C.	200mm
D.	80mm
Answer» C. 200mm

Discussion

14.	If worm helix angle is 30⁰, then worm should have at least ___ threads.
A.	5
B.	6
C.	7
D.	8
Answer» B. 6

Discussion

15.	The axial thrust on the worm (WA) is given by
A.	is given bya) WA = WT . tan φ
B.	WA = WT / tan φ
C.	WA = WT . tan λ
D.	WA = WT / tan λ
Answer» E.

Discussion

16.	The number of starts on the worm for a velocity ratio of 40 should be
A.	single
B.	double
C.	triple
D.	quadruple
Answer» B. double

Discussion

17.	The normal lead, in a worm having multiple start threads, is given by
A.	lN = l / cos λ
B.	lN = l . cos λ
C.	lN = l
D.	lN = l tan
Answer» C. lN = l

Discussion

18.	A_PAIR_OF_WORM_GEAR_IS_WRITTEN_AS_2/40/12/6._CALCULATE_THE_SPEED_REDUCTION.?$
A.	2
B.	20
C.	15
D.	6
Answer» C. 15

Discussion

19.	WHAT_IS_THE_FORMULA_TO_CALCULATE_MAXIMUM_EFFICIENCY_OF_A_WORM_GEAR??$
A.	(1+sin‚Äö√†√∂‚Äö√†√®)/(1-sin‚Äö√†√∂‚Äö√†√®)
B.	(1-sin‚Äö√†√∂‚Äö√†√®)/(1+sin‚Äö√†√∂‚Äö√†√®)
C.	(tan(‚âà√≠¬¨‚Ñ¢<sub>1</sub>-‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢<sub>1</sub>
D.	(tan(‚âà√≠¬¨‚Ñ¢<sub>1</sub>+‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢<sub>1</sub>
Answer» C. (tan(‚âà√≠¬¨‚Ñ¢<sub>1</sub>-‚Äö√†√∂‚Äö√†√®))/tan ‚âà√≠¬¨‚Ñ¢<sub>1</sub>

Discussion

20.	THE_NUMBER_OF_STARTS_ON_THE_WORM_FOR_A_VELOCITY_RATIO_OF_40_SHOULD_BE?$
A.	single
B.	double
C.	triple
D.	quadruple
Answer» B. double

Discussion

21.	A pair of worm gear is written as 2/40/12/6. Calculate the throat diameter of the worm wheel.$
A.	220.5mm
B.	246.4mm
C.	190.44mm
D.	251.7mm
Answer» E.

Discussion

22.	Find the speed of the gear if the worm is a three start worm rotating at 500 rpm. The gear has 20 teeth.$
A.	125 rpm
B.	100 rpm
C.	75 rpm
D.	50 rpm
Answer» D. 50 rpm

Discussion

23.	A pair of worm gear is written as 2/40/12/6. Calculate the pitch circle diameter of worm wheel.$
A.	72mm
B.	240mm
C.	260mm
D.	320mm
Answer» C. 260mm

Discussion

24.	Find_the_helix_angle_of_the_worm_if_the_pitch_of_the_worm_gear_is_12_mm_and_the_pitch_diameter_is_50_mm.$
A.	8.687¬¨¬®‚Äö√†√ª
B.	11.231¬¨¬®‚Äö√†√ª
C.	9.212¬¨¬®‚Äö√†√ª
D.	10.319¬¨¬®‚Äö√†√ª
Answer» B. 11.231¬¨¬®‚Äö√†√ª

Discussion

25.	The_axial_thrust_on_the_worm_(W_A)_is_given_by$
A.	W<sub>A</sub> = W<sub>T</sub> . tan ‚âà√¨‚àö√∫
B.	W<sub>A</sub> = W<sub>T</sub> / tan ‚âà√¨‚àö√∫
C.	W<sub>A</sub> = W<sub>T</sub> . tan ‚âà√≠¬¨‚Ñ¢
D.	W<sub>A</sub> = W<sub>T</sub> / tan ‚âà√≠¬¨‚Ñ¢
Answer» E.

Discussion

26.	Calculate the maximum efficiency of the worm gears which have a friction angle of 0.06.
A.	88.71%
B.	83.23%
C.	89.91%
D.	86.49%
Answer» B. 83.23%

Discussion

27.	Find the maximum efficiency if the lead angle is given to be 10¬¨¬®‚Äö√†√ª and the coefficient of friction is 0.07.$
A.	79.82%
B.	72.23%
C.	76.29%
D.	70.72%
Answer» E.

Discussion

28.	22mm
A.	250.4mm
B.	225.6mm
C.	250.44mm
Answer» B. 225.6mm

Discussion

29.	Calculate the lead angle of the worm gear for maximum efficiency if ‚âà√≠‚Äö√†√® = 90¬¨¬®‚Äö√†√ª and the coefficient of friction is 0.05.$
A.	48.21¬¨¬®‚Äö√†√ª
B.	42.23¬¨¬®‚Äö√†√ª
C.	43.57¬¨¬®‚Äö√†√ª
D.	46.43¬¨¬®‚Äö√†√ª
Answer» D. 46.43¬¨¬®‚Äö√†√ª

Discussion

30.	For a two start worm gear having a pitch of 20 mm and a lead angle 12¬¨¬®‚Äö√†√ª, find the centre distance if the larger gear has 25 teeth.$
A.	148.22 mm
B.	124.93 mm
C.	121.19 mm
D.	109.53 mm
Answer» E.

Discussion

31.	A pair of worm gear is written as 2/40/12/6. Calculate the centre distance?
A.	40mm
B.	156mm
C.	200mm
D.	80mm
Answer» C. 200mm

Discussion

32.	What is the centre distance for the worm gear?
A.	(m<sub>n</sub>/2)(T<sub>1</sub> cot‚âà√≠¬¨‚Ñ¢<sub>1</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® T<sub>2</sub>)
B.	(m<sub>n</sub>/2)(T<sub>2</sub> cot‚âà√≠¬¨‚Ñ¢<sub>1</sub> + T<sub>1</sub>)
C.	(m<sub>n</sub>/2)(T<sub>2</sub> cot‚âà√≠¬¨‚Ñ¢<sub>1</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® T<sub>1</sub>)
D.	(m<sub>n</sub>/2)(T<sub>1</sub> cot‚âà√≠¬¨‚Ñ¢<sub>1</sub> + T<sub>2</sub>)
Answer» E.

Discussion

33.	The normal lead, in a worm having multiple start threads, is given b?
A.	l<sub>N</sub> = l / cos ‚âà√≠¬¨‚Ñ¢
B.	l<sub>N</sub> = l . cos ‚âà√≠¬¨‚Ñ¢
C.	l<sub>N</sub> = l
D.	l<sub>N</sub> = l tan
Answer» C. l<sub>N</sub> = l

Discussion

34.	If worm helix angle is 30‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª, then worm should have at least ___ threads.$
A.	5
B.	6
C.	7
D.	8
Answer» B. 6

Discussion

35.	What is the velocity ratio of worm gears?
A.	(l‚âà√¨‚àö√ë)/d<sub>2</sub>
B.	(‚âà√¨‚àö√ëd<sub>2</sub>)/l
C.	l/(‚âà√¨‚àö√ëd<sub>2</sub>)
D.	d<sub>2</sub>/(l‚âà√¨‚àö√ë)
Answer» D. d<sub>2</sub>/(l‚âà√¨‚àö√ë)

Discussion

36.	In worm gears, the angle between the tangent to the thread helix on the pitch cylinder and the plane normal to the axis of worm is called
A.	pressure angle
B.	lead angle
C.	helix angle
D.	friction angle
Answer» C. helix angle

Discussion

37.	The worm helix angle is the _____ of the worm lead angle.
A.	Complement
B.	Half
C.	Double
D.	Supplement
Answer» B. Half

Discussion

38.	The angle at which the teeth are inclined to the normal of the axis of rotation is called _______________
A.	pitch angle
B.	lead angle
C.	normal angle
D.	joint angle
Answer» C. normal angle

Discussion

39.	The worm gears are widely used for transmitting power at ______________ velocity ratios between non-intersecting shafts.
A.	high
B.	low
C.	medium
D.	none of the mentioned
Answer» B. low

Discussion

40.	Can worm gears be used in steering mechanism?
A.	True
B.	False
Answer» B. False

Discussion

41.	The distance by which a helix advances along the axis of the gear for one turn around is called _____________
A.	joint line
B.	normal link
C.	axial pitch
D.	lead
Answer» E.

Discussion

42.	For a bevel gear having the pitch angle ‚âà√≠‚Äö√†√®, the ratio of formative number of teeth (T_E) to actual number of teeth (T) is$
A.	1/sin ‚âà√≠‚Äö√†√®
B.	1/cos ‚âà√≠‚Äö√†√®
C.	1/tan ‚âà√≠‚Äö√†√®
D.	sin ‚âà√≠‚Äö√†√® cos ‚âà√≠‚Äö√†√®
Answer» C. 1/tan ‚âà√≠‚Äö√†√®

Discussion

43.	The power transmitting capacity of worm gears is high although efficiency is low.
A.	True
B.	False
Answer» C.

Discussion

44.	The distance between corresponding points on adjacent teeth measured along the direction of the axis is called ____________
A.	joint line
B.	normal link
C.	axial pitch
D.	lead
Answer» D. lead

Discussion

45.	If b denotes the face width and L denotes the cone distance, then the bevel factor is written as
A.	b / L
B.	b / 2L
C.	1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® 2 b.L
D.	1 ‚Äö√Ñ√∂‚àö√ë‚àö¬® b / L
Answer» E.

Discussion

46.	Is it possible to use worm gears in cranes for lifting purpose?
A.	True
B.	No self-locking and hence not possible
C.	Possible up to a threshold load
D.	None of the listed
Answer» B. No self-locking and hence not possible

Discussion

47.	Which is of these is an advantage of worm gear?
A.	It is expensive
B.	Has high power losses and low transmission efficiency
C.	Produce a lot of heat
D.	Used for reducing speed and increasing torque
Answer» E.

Discussion

48.	Which of the following is not true about worm gears?
A.	Compact
B.	Smooth and silent operation
C.	Low speed reduction
D.	All the mentioned are true
Answer» D. All the mentioned are true

Discussion

49.	The driven gear in the worm gear is a helical gear. True or false?
A.	True
B.	False
Answer» B. False

Discussion

50.	The face angle of a bevel gear is equal to
A.	pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® addendum angle
B.	pitch angle + addendum angle
C.	pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® dedendum angle
D.	pitch angle + dedendum angle
Answer» C. pitch angle ‚Äö√Ñ√∂‚àö√ë‚àö¬® dedendum angle

Discussion

Explore topic-wise MCQs in Machine Design.

Find the maximum efficiency if the lead angle is given to be 10° and the coefficient of friction is 0.07.

Calculate the lead angle of the worm gear for maximum efficiency if θ = 90° and the coefficient of friction is 0.05.

For a two start worm gear having a pitch of 20 mm and a lead angle 12°, find the centre distance if the larger gear has 25 teeth.

Find the speed of the gear if the worm is a three start worm rotating at 500 rpm. The gear has 20 teeth.

Find the helix angle of the worm if the pitch of the worm gear is 12 mm and the pitch diameter is 50 mm.

What is the formula to calculate maximum efficiency of a worm gear?

When large gear reductions are needed _________ gears are used.

If tangential force on worm is 1500N, then axial force on worm wheel will be?

A pair of worm gear is written as 2/40/12/6. Calculate the root diameter of the worm wheel.

A pair of worm gear is written as 2/40/12/6. Calculate the throat diameter of the worm wheel.

A pair of worm gear is written as 2/40/12/6. Calculate the pitch circle diameter of worm wheel.

A pair of worm gear is written as 2/40/12/6. Calculate the speed reduction.

A pair of worm gear is written as 2/40/12/6. Calculate the centre distance.

If worm helix angle is 30⁰, then worm should have at least ___ threads.

The axial thrust on the worm (WA) is given by

The number of starts on the worm for a velocity ratio of 40 should be

The normal lead, in a worm having multiple start threads, is given by

A_PAIR_OF_WORM_GEAR_IS_WRITTEN_AS_2/40/12/6._CALCULATE_THE_SPEED_REDUCTION.?$

WHAT_IS_THE_FORMULA_TO_CALCULATE_MAXIMUM_EFFICIENCY_OF_A_WORM_GEAR??$

THE_NUMBER_OF_STARTS_ON_THE_WORM_FOR_A_VELOCITY_RATIO_OF_40_SHOULD_BE?$

A pair of worm gear is written as 2/40/12/6. Calculate the throat diameter of the worm wheel.$

Find the speed of the gear if the worm is a three start worm rotating at 500 rpm. The gear has 20 teeth.$

A pair of worm gear is written as 2/40/12/6. Calculate the pitch circle diameter of worm wheel.$

Find_the_helix_angle_of_the_worm_if_the_pitch_of_the_worm_gear_is_12_mm_and_the_pitch_diameter_is_50_mm.$

The_axial_thrust_on_the_worm_(WA)_is_given_by$

Calculate the maximum efficiency of the worm gears which have a friction angle of 0.06.

Find the maximum efficiency if the lead angle is given to be 10¬¨¬®‚Äö√†√ª and the coefficient of friction is 0.07.$

22mm

Calculate the lead angle of the worm gear for maximum efficiency if ‚âà√≠‚Äö√†√® = 90¬¨¬®‚Äö√†√ª and the coefficient of friction is 0.05.$

For a two start worm gear having a pitch of 20 mm and a lead angle 12¬¨¬®‚Äö√†√ª, find the centre distance if the larger gear has 25 teeth.$

A pair of worm gear is written as 2/40/12/6. Calculate the centre distance?

What is the centre distance for the worm gear?

The normal lead, in a worm having multiple start threads, is given b?

If worm helix angle is 30‚Äö√Ñ√∂‚àö√ñ‚Äö√†√ª, then worm should have at least ___ threads.$

What is the velocity ratio of worm gears?

In worm gears, the angle between the tangent to the thread helix on the pitch cylinder and the plane normal to the axis of worm is called

The worm helix angle is the _____ of the worm lead angle.

The angle at which the teeth are inclined to the normal of the axis of rotation is called _______________

The worm gears are widely used for transmitting power at ______________ velocity ratios between non-intersecting shafts.

Can worm gears be used in steering mechanism?

The distance by which a helix advances along the axis of the gear for one turn around is called _____________

For a bevel gear having the pitch angle ‚âà√≠‚Äö√†√®, the ratio of formative number of teeth (TE) to actual number of teeth (T) is$

The power transmitting capacity of worm gears is high although efficiency is low.

The distance between corresponding points on adjacent teeth measured along the direction of the axis is called ____________

If b denotes the face width and L denotes the cone distance, then the bevel factor is written as

Is it possible to use worm gears in cranes for lifting purpose?

Which is of these is an advantage of worm gear?

Which of the following is not true about worm gears?

The driven gear in the worm gear is a helical gear. True or false?

The face angle of a bevel gear is equal to

The_axial_thrust_on_the_worm_(W_A)_is_given_by$

For a bevel gear having the pitch angle ‚âà√≠‚Äö√†√®, the ratio of formative number of teeth (T_E) to actual number of teeth (T) is$