MCQOPTIONS
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MCQOPTIONS
This section includes 27 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Validate the statement “Because of High frequency emphasis the gray-level tonality due to low frequency components is not lost”. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 2. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. When b increases past 1 the filtering process is specifically termed as__________ |
| A. | Unsharp masking |
| B. | High-boost filtering |
| C. | Emphasized filtering |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 3. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. What happens when b increases past 1? |
| A. | The high frequency are emphasized |
| B. | The low frequency are emphasized |
| C. | All frequency are emphasized |
| D. | None of the mentioned |
| Answer» B. The low frequency are emphasized | |
| 4. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. for certain values of a and b it reduces to High-boost filtering. Which of the following is the required value? |
| A. | a = (A-1) and b = 0,A is some constant |
| B. | a = 0 and b = (A-1),A is some constant |
| C. | a = 1 and b = 1 |
| D. | a = (A-1) and b =1,A is some constant |
| Answer» E. | |
| 5. |
Which of the following a transfer function of High frequency emphasis {Hhfe(u, v)} for Hhp(u, v) being the highpass filtered version of image? |
| A. | Hhfe(u, v) = 1 – Hhp(u, v) |
| B. | Hhfe(u, v) = a – Hhp(u, v), a≥0 |
| C. | Hhfe(u, v) = 1 – b Hhp(u, v), a≥0 and b>a |
| D. | Hhfe(u, v) = a + b Hhp(u, v), a≥0 and b>a |
| Answer» E. | |
| 6. |
A process that accentuate the contribution to enhancement made by high-frequency components, by multiplying the highpass filter by a constant and adding an offset to the highpass filter to prevent eliminating zero frequency term by filter is known as _______ |
| A. | Unsharp masking |
| B. | High-boost filtering |
| C. | High frequency emphasis |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 7. |
To accentuate the contribution to enhancement made by high-frequency components, which of the following method(s) should be more appropriate to apply? |
| A. | Multiply the highpass filter by a constant |
| B. | Add an offset to the highpass filter to prevent eliminating zero frequency term by filter |
| C. | All of the mentioned combined and applied |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 8. |
If unsharp masking can be implemented directly in frequency domain by using a composite filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. Then, the composite filter for High-boost filtering is __________ |
| A. | Hhb(u, v) = 1 – Hhp(u, v) |
| B. | Hhb(u, v) = 1 + Hhp(u, v) |
| C. | Hhb(u, v) = (A-1) – Hhp(u, v), A is a constant |
| D. | Hhb(u, v) = (A-1) + Hhp(u, v), A is a constant |
| Answer» E. | |
| 9. |
Unsharp masking can be implemented directly in frequency domain by using a filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. What kind of filter is Hhp(u, v)? |
| A. | Composite filter |
| B. | M-derived filter |
| C. | Constant k filter |
| D. | None of the mentioned |
| Answer» B. M-derived filter | |
| 10. |
If, Fhp(u, v)=F(u, v) – Flp(u, v) and Flp(u, v) = Hlp(u, v)F(u, v), where F(u, v) is the image in frequency domain with Fhp(u, v) its highpass filtered version, Flp(u, v) its lowpass filtered component and Hlp(u, v) the transfer function of a lowpass filter. Then, unsharp masking can be implemented directly in frequency domain by using a filter. Which of the following is the required filter? |
| A. | Hhp(u, v) = Hlp(u, v) |
| B. | Hhp(u, v) = 1 + Hlp(u, v) |
| C. | Hhp(u, v) = – Hlp(u, v) |
| D. | Hhp(u, v) = 1 – Hlp(u, v) |
| Answer» E. | |
| 11. |
High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact(s) validates if A increases past 1? |
| A. | The contribution of the image itself becomes more dominant |
| B. | The contribution of the highpass filtered version of image becomes less dominant |
| C. | All of the mentioned |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 12. |
High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1? |
| A. | High-boost filtering reduces to regular Highpass filtering |
| B. | High-boost filtering reduces to regular Lowpass filtering |
| C. | All of the mentioned |
| D. | None of the mentioned |
| Answer» B. High-boost filtering reduces to regular Lowpass filtering | |
| 13. |
In frequency domain terminology, which of the following is defined as “obtaining a highpass filtered image by subtracting from the given image a lowpass filtered version of itself”? |
| A. | Emphasis filtering |
| B. | Unsharp masking |
| C. | Butterworth filtering |
| D. | None of the mentioned |
| Answer» C. Butterworth filtering | |
| 14. |
TO_ACCENTUATE_THE_CONTRIBUTION_TO_ENHANCEMENT_MADE_BY_HIGH-FREQUENCY_COMPONENTS,_WHICH_OF_THE_FOLLOWING_METHOD(S)_SHOULD_BE_MORE_APPROPRIATE_TO_APPLY??$ |
| A. | Multiply the highpass filter by a constant |
| B. | Add an offset to the highpass filter to prevent eliminating zero frequency term by filter |
| C. | All of the mentioned combined and applied |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 15. |
Which of the following a transfer function of High frequency emphasis {Hhfe(u, v)} for Hhp(u, v) being the highpass filtered version of image?$ |
| A. | H<sub>hfe</sub>(u, v) = 1 – H<sub>hp</sub>(u, v) |
| B. | H<sub>hfe</sub>(u, v) = a – H<sub>hp</sub>(u, v), a≥0 |
| C. | H<sub>hfe</sub>(u, v) = 1 – b H<sub>hp</sub>(u, v), a≥0 and b>a |
| D. | H<sub>hfe</sub>(u, v) = a + b H<sub>hp</sub>(u, v), a‚â•0 and b>a |
| Answer» E. | |
| 16. |
A_process_that_accentuate_the_contribution_to_enhancement_made_by_high-frequency_components,_by_multiplying_the_highpass_filter_by_a_constant_and_adding_an_offset_to_the_highpass_filter_to_prevent_eliminating_zero_frequency_term_by_filter_is_known_as________$ |
| A. | Unsharp masking |
| B. | High-boost filtering |
| C. | High frequency emphasis |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 17. |
Validate the statement “Because of High frequency emphasis the gray-level tonality due to low frequency components is not lost”.$ |
| A. | True |
| B. | False |
| Answer» B. False | |
| 18. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a‚â•0 and b>a. When b increases past 1 the filtering process is specifically termed as__________$ |
| A. | Unsharp masking |
| B. | High-boost filtering |
| C. | Emphasized filtering |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 19. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a‚â•0 and b>a. What happens when b increases past 1?$ |
| A. | The high frequency are emphasized |
| B. | The low frequency are emphasized |
| C. | All frequency are emphasized |
| D. | None of the mentioned |
| Answer» B. The low frequency are emphasized | |
| 20. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a‚â•0 and b>a. for certain values of a and b it reduces to High-boost filtering. Which of the following is the required value?$ |
| A. | a = (A-1) and b = 0,A is some constant |
| B. | a = 0 and b = (A-1),A is some constant |
| C. | a = 1 and b = 1 |
| D. | a = (A-1) and b =1,A is some constant |
| Answer» E. | |
| 21. |
The frequency domain Laplacian is closer to which of the following mask? |
| A. | Mask that excludes the diagonal neighbors |
| B. | Mask that excludes neighbors in 4-adjacancy |
| C. | Mask that excludes neighbors in 8-adjacancy |
| D. | None of the mentioned |
| Answer» B. Mask that excludes neighbors in 4-adjacancy | |
| 22. |
If unsharp masking can be implemented directly in frequency domain by using a composite filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. Then, the composite filter for High-boost filtering is __________$ |
| A. | H<sub>hb</sub>(u, v) = 1 – H<sub>hp</sub>(u, v) |
| B. | H<sub>hb</sub>(u, v) = 1 + H<sub>hp</sub>(u, v) |
| C. | H<sub>hb</sub>(u, v) = (A-1) – H<sub>hp</sub>(u, v), A is a constant |
| D. | H<sub>hb</sub>(u, v) = (A-1) + H<sub>hp</sub>(u, v), A is a constant |
| Answer» E. | |
| 23. |
Unsharp masking can be implemented directly in frequency domain by using a filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. What kind of filter is Hhp(u, v)?$ |
| A. | Composite filter |
| B. | M-derived filter |
| C. | Constant k filter |
| D. | None of the mentioned |
| Answer» B. M-derived filter | |
| 24. |
If, Fhp(u, v)=F(u, v) – Flp(u, v) and Flp(u, v) = Hlp(u, v)F(u, v), where F(u, v) is the image in frequency domain with Fhp(u, v) its highpass filtered version, Flp(u, v) its lowpass filtered component and Hlp(u, v) the transfer function of a lowpass filter. Then, unsharp masking can be implemented directly in frequency domain by using a filter. Which of the following is the required filter?$ |
| A. | H<sub>hp</sub>(u, v) = H<sub>lp</sub>(u, v) |
| B. | H<sub>hp</sub>(u, v) = 1 + H<sub>lp</sub>(u, v) |
| C. | H<sub>hp</sub>(u, v) = – H<sub>lp</sub>(u, v) |
| D. | H<sub>hp</sub>(u, v) = 1 – H<sub>lp</sub>(u, v) |
| Answer» E. | |
| 25. |
High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1?$ |
| A. | High-boost filtering reduces to regular Highpass filtering |
| B. | High-boost filtering reduces to regular Lowpass filtering |
| C. | All of the mentioned |
| D. | None of the mentioned |
| Answer» B. High-boost filtering reduces to regular Lowpass filtering | |
| 26. |
Which of the following is/ are a generalized form of unsharp masking? |
| A. | Lowpass filtering |
| B. | High-boost filtering |
| C. | Emphasis filtering |
| D. | All of the mentioned |
| Answer» C. Emphasis filtering | |
| 27. |
In frequency domain terminology, which of the following is defined as “obtaining a highpass filtered image by subtracting from the given image a lowpass filtered version of itself”? |
| A. | Emphasis filtering |
| B. | Unsharp masking |
| C. | Butterworth filtering |
| D. | None of the mentioned |
| Answer» C. Butterworth filtering | |