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This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Image Processing knowledge and support exam preparation. Choose a topic below to get started.
1. |
Validate the statement Because of High frequency emphasis the gray-level tonality due to low frequency components is not lost . |
A. | tTrue |
B. | tFalse |
Answer» B. tFalse | |
2. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a 0 and b>a. When b increases past 1 the filtering process is specifically termed as__________ |
A. | tUnsharp masking |
B. | tHigh-boost filtering |
C. | tEmphasized filtering |
D. | tNone of the mentioned |
Answer» D. tNone of the mentioned | |
3. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a 0 and b>a. What happens when b increases past 1? |
A. | tThe high frequency are emphasized |
B. | tThe low frequency are emphasized |
C. | tAll frequency are emphasized |
D. | tNone of the mentioned |
Answer» B. tThe low frequency are emphasized | |
4. |
The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a 0 and b>a. for certain values of a and b it reduces to High-boost filtering. Which of the following is the required value? |
A. | ta = (A-1) and b = 0,A is some constant |
B. | ta = 0 and b = (A-1),A is some constant |
C. | ta = 1 and b = 1 |
D. | ta = (A-1) and b =1,A is some constant |
Answer» E. | |
5. |
Which of the following a transfer function of High frequency emphasis {Hhfe(u, v)} for Hhp(u, v) being the highpass filtered version of image? |
A. | tH<sub>hfe</sub>(u, v) = 1 H<sub>hp</sub>(u, v) |
B. | tH<sub>hfe</sub>(u, v) = a H<sub>hp</sub>(u, v), a 0 |
C. | tH<sub>hfe</sub>(u, v) = 1 b H<sub>hp</sub>(u, v), a 0 and b>a |
D. | tH<sub>hfe</sub>(u, v) = a + b H<sub>hp</sub>(u, v), a 0 and b>a |
Answer» E. | |
6. |
A process that accentuate the contribution to enhancement made by high-frequency components, by multiplying the highpass filter by a constant and adding an offset to the highpass filter to prevent eliminating zero frequency term by filter is known as _______ |
A. | tUnsharp masking |
B. | tHigh-boost filtering |
C. | tHigh frequency emphasis |
D. | tNone of the mentioned |
Answer» D. tNone of the mentioned | |
7. |
To accentuate the contribution to enhancement made by high-frequency components, which of the following method(s) should be more appropriate to apply? |
A. | tMultiply the highpass filter by a constant |
B. | tAdd an offset to the highpass filter to prevent eliminating zero frequency term by filter |
C. | tAll of the mentioned combined and applied |
D. | tNone of the mentioned |
Answer» D. tNone of the mentioned | |
8. |
If unsharp masking can be implemented directly in frequency domain by using a composite filter: Hhp(u, v) = 1 Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. Then, the composite filter for High-boost filtering is __________ |
A. | tH<sub>hb</sub>(u, v) = 1 H<sub>hp</sub>(u, v) |
B. | tH<sub>hb</sub>(u, v) = 1 + H<sub>hp</sub>(u, v) |
C. | tH<sub>hb</sub>(u, v) = (A-1) H<sub>hp</sub>(u, v), A is a constant |
D. | tH<sub>hb</sub>(u, v) = (A-1) + H<sub>hp</sub>(u, v), A is a constant |
Answer» E. | |
9. |
Unsharp masking can be implemented directly in frequency domain by using a filter: Hhp(u, v) = 1 Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. What kind of filter is Hhp(u, v)? |
A. | tComposite filter |
B. | tM-derived filter |
C. | tConstant k filter |
D. | tNone of the mentioned |
Answer» B. tM-derived filter | |
10. |
If, Fhp(u, v)=F(u, v) Flp(u, v) and Flp(u, v) = Hlp(u, v)F(u, v), where F(u, v) is the image in frequency domain with Fhp(u, v) its highpass filtered version, Flp(u, v) its lowpass filtered component and Hlp(u, v) the transfer function of a lowpass filter. Then, unsharp masking can be implemented directly in frequency domain by using a filter. Which of the following is the required filter? |
A. | tH<sub>hp</sub>(u, v) = H<sub>lp</sub>(u, v) |
B. | tH<sub>hp</sub>(u, v) = 1 + H<sub>lp</sub>(u, v) |
C. | tH<sub>hp</sub>(u, v) = H<sub>lp</sub>(u, v) |
D. | tH<sub>hp</sub>(u, v) = 1 H<sub>lp</sub>(u, v) |
Answer» E. | |
11. |
High boost filtered image is expressed as: fhb = A f(x, y) flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact(s) validates if A increases past 1? |
A. | tThe contribution of the image itself becomes more dominant |
B. | tThe contribution of the highpass filtered version of image becomes less dominant |
C. | tAll of the mentioned |
D. | tNone of the mentioned |
Answer» D. tNone of the mentioned | |
12. |
High boost filtered image is expressed as: fhb = A f(x, y) flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1? |
A. | tHigh-boost filtering reduces to regular Highpass filtering |
B. | tHigh-boost filtering reduces to regular Lowpass filtering |
C. | tAll of the mentioned |
D. | tNone of the mentioned |
Answer» B. tHigh-boost filtering reduces to regular Lowpass filtering | |
13. |
In frequency domain terminology, which of the following is defined as obtaining a highpass filtered image by subtracting from the given image a lowpass filtered version of itself ? |
A. | tEmphasis filtering |
B. | tUnsharp masking |
C. | tButterworth filtering |
D. | tNone of the mentioned |
Answer» C. tButterworth filtering | |