MCQOPTIONS
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MCQOPTIONS
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In the equation x(t) = a(t)cos[2 Fct+ (t)], Which of the following relations between a(t) and x(t), (t) and x(t) are true? |
| A. | a(t), (t) are called the Phases of x(t) |
| B. | a(t) is the Phase of x(t), (t) is called the Envelope of x(t) |
| C. | a(t) is the Envelope of x(t), (t) is called the Phase of x(t) |
| D. | none of the mentioned |
| Answer» D. none of the mentioned | |
| 2. |
What is the possible representation of x(t) if xl(t)=a(t)e(j (t))? |
| A. | x(t) = a(t) cos[2 F<sub>c</sub>t (t)] |
| B. | x(t) = a(t) cos[2 F<sub>c</sub>t + (t)] |
| C. | x(t) = a(t) sin[2 F<sub>c</sub>t + (t)] |
| D. | x(t) = a(t) sin[2 F<sub>c</sub>t (t)] |
| Answer» C. x(t) = a(t) sin[2 F<sub>c</sub>t + (t)] | |
| 3. |
If a possible representation of a band pass signal is obtained by expressing xl (t) as (x_l (t)=a(t)e^{j (t}) ) then what are the equations of a(t) and (t)? |
| A. | a(t) = ( sqrt{u_c^2 (t)+u_s^2 (t)} ) and (t)= (tan^{-1} frac{u_s (t)}{u_c (t)} ) |
| B. | a(t) = ( sqrt{u_c^2 (t)-u_s^2 (t)} ) and (t)= (tan^{-1} frac{u_s (t)}{u_c (t)} ) |
| C. | a(t) = ( sqrt{u_c^2 (t)+u_s^2 (t)} ) and (t)= (tan^{-1} frac{u_c (t)}{u_s (t)} ) |
| D. | a(t) = ( sqrt{u_s^2 (t)-u_c^2 (t)} ) and (t)= (tan^{-1} u2061 frac{u_s (t)}{u_c (t)} ) |
| Answer» B. a(t) = ( sqrt{u_c^2 (t)-u_s^2 (t)} ) and (t)= (tan^{-1} frac{u_s (t)}{u_c (t)} ) | |
| 4. |
In the equation x(t) = Re ([x_l (t) e^{j2 F_c t}] ), What is the lowpass signal xl (t) is usually called the ___ of the real signal x(t). |
| A. | Mediature envelope |
| B. | Complex envelope |
| C. | Equivalent envelope |
| D. | All of the mentioned |
| Answer» C. Equivalent envelope | |
| 5. |
What is the other way of representation of bandpass signal x(t)? |
| A. | x(t) = R<sub>e</sub> ([x_l (t) e^{j2 F_c t}] ) |
| B. | x(t) = R<sub>e</sub> ([x_l (t) e^{j F_c t}] ) |
| C. | x(t) = R<sub>e</sub> ([x_l (t) e^{j4 F_c t}] ) |
| D. | x(t) = R<sub>e</sub> ([x_l (t) e^{j0 F_c t}] ) |
| Answer» B. x(t) = R<sub>e</sub> ([x_l (t) e^{j F_c t}] ) | |
| 6. |
In the relation, x(t) = (u_c (t) cos 2 ,F_c ,t-u_s (t) sin 2 ,F_c ,t ) the low frequency components uc and us are called _____________ of the bandpass signal x(t). |
| A. | Quadratic components |
| B. | Quadrature components |
| C. | Triplet components |
| D. | None of the mentioned |
| Answer» C. Triplet components | |
| 7. |
If we substitute the equation (x_l (t)= u_c (t)+j u_s (t) ) in equation x (t) + j (t) = xl(t) ej2 Fct and equate real and imaginary parts on side, then what are the relations that we obtain? |
| A. | x(t)= (u_c (t) ,cos u20612 ,F_c ,t+u_s (t) ,sin u20612 ,F_c ,t ); (t)= (u_s (t) ,cos u20612 ,F_c ,t-u_c ,(t) ,sin u20612 ,F_c ,t ) |
| B. | x(t)= (u_c (t) ,cos u20612 ,F_c ,t-u_s (t) ,sin u20612 ,F_c ,t ); (t)= (u_s (t) ,cos u20612 ,F_c t+u_c (t) ,sin u20612 ,F_c ,t ) |
| C. | x(t)= (u_c (t) ,cos u20612 ,F_c t+u_s (t) ,sin u20612 ,F_c ,t ); (t)= (u_s (t) ,cos u20612 ,F_c t+u_c (t) ,sin u20612 ,F_c ,t ) |
| D. | x(t)= (u_c (t) ,cos u20612 ,F_c ,t-u_s (t) ,sin u20612 ,F_c ,t ); (t)= (u_s (t) ,cos u20612 ,F_c ,t-u_c (t) ,sin u20612 ,F_c ,t ) |
| Answer» C. x(t)= (u_c (t) ,cos u20612 ,F_c t+u_s (t) ,sin u20612 ,F_c ,t ); (t)= (u_s (t) ,cos u20612 ,F_c t+u_c (t) ,sin u20612 ,F_c ,t ) | |
| 8. |
What is the equivalent time domain relation of xl(t) i.e., lowpass signal? |
| A. | (x_l (t)=[x(t)+j (t)]e^{-j2 F_c t} ) |
| B. | x(t)+j (t) = (x_l (t) e^{j2 F_c t} ) |
| C. | (x_l (t)=[x(t)+j (t)]e^{-j2 F_c t} ) & x(t)+j (t) = (x_l (t) e^{j2 F_c t} ) |
| D. | None of the mentioned |
| Answer» D. None of the mentioned | |
| 9. |
What is the frequency response of a Hilbert transform H(F)=? |
| A. | ( begin{cases}&-j (F>0) & 0 (F=0) & j (F<0) end{cases} ) |
| B. | ( left { begin{matrix}-j & (F<0) 0 & (F=0) j & (F>0) end{matrix} right. ) |
| C. | ( left { begin{matrix}-j & (F>0) 0 &(F=0) j & (F<0) end{matrix} right. ) |
| D. | ( left { begin{matrix}j&(F>0) 0 & (F=0) j & (F<0) end{matrix} right. ) |
| Answer» B. ( left { begin{matrix}-j & (F<0) 0 & (F=0) j & (F>0) end{matrix} right. ) | |
| 10. |
If the signal (t) can be viewed as the output of the filter with impulse response h(t) = 1/ t, - < t < when excited by the input signal x(t) then such a filter is called as __________ |
| A. | Analytic transformer |
| B. | Hilbert transformer |
| C. | Both Analytic & Hilbert transformer |
| D. | None of the mentioned |
| Answer» C. Both Analytic & Hilbert transformer | |
| 11. |
In equation (x_+ (t)=F^{-1} [2V(F)]*F^{-1} [X(F)] ), if (F^{-1} [2V(F)]= (t)+j/ t ) and (F^{-1} [X(F)] ) = x(t). Then the value of (t) is? |
| A. | ( frac{1}{ } int_{- infty}^ infty frac{x(t)}{t+ } d ) |
| B. | ( frac{1}{ } int_{- infty}^ infty frac{x(t)}{t- } d ) |
| C. | ( frac{1}{ } int_{- infty}^ infty frac{2x(t)}{t- } d ) |
| D. | ( frac{1}{ } int_{- infty}^ infty frac{4x(t)}{t- } d ) |
| Answer» C. ( frac{1}{ } int_{- infty}^ infty frac{2x(t)}{t- } d ) | |
| 12. |
In time-domain expression, (x_+ (t)=F^{-1} [2V(F)]*F^{-1} [X(F)] ). The signal x+(t) is known as |
| A. | Systematic signal |
| B. | Analytic signal |
| C. | Pre-envelope of x(t) |
| D. | Both Analytic signal & Pre-envelope of x(t) |
| Answer» E. | |
| 13. |
What is the equivalent time domain expression of X+(F)=2V(F)X(F)? |
| A. | F<sup>(+1)</sup>[2V(F)]*F<sup>(+1)</sup>[X(F)] |
| B. | F<sup>(-1)</sup>[4V(F)]*F<sup>(-1)</sup>[X(F)] |
| C. | F<sup>(-1)</sup>[V(F)]*F<sup>(-1)</sup>[X(F)] |
| D. | F<sup>(-1)</sup>[2V(F)]*F<sup>(-1)</sup>[X(F)] |
| Answer» E. | |