MCQOPTIONS
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MCQOPTIONS
This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Pavement Design knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which temperature stress is generally ignored in the design? |
| A. | Frictional stress |
| B. | Interior stress |
| C. | Edge stress |
| D. | Corner stress |
| Answer» E. | |
| 2. |
What would be the frictional stress if the spacing between contraction joints is 5 m, the coefficient of friction is 1.5 and the unit weight of concrete is 2400 kg/m3? |
| A. | 0.9 kg/cm<sup>2</sup> |
| B. | 0.88 kg/cm<sup>2</sup> |
| C. | 0.8 kg/cm<sup>2</sup> |
| D. | 0.99 kg/cm<sup>2</sup> |
| Answer» B. 0.88 kg/cm<sup>2</sup> | |
| 3. |
How was the temperature stress analysis done by J. Thomlinson? |
| A. | Thermometers |
| B. | Thermocouples |
| C. | Thermostats |
| D. | Thermocline |
| Answer» C. Thermostats | |
| 4. |
The temperature differential is affected by the geographical features of the pavement location. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 5. |
What would be the frictional stress if the spacing between contraction joints is 4.2 m, the coefficient of friction is 1.3 and the unit weight of concrete is 2400 kg/m3? |
| A. | 0.66 kg/cm<sup>2</sup> |
| B. | 0.70 kg/cm<sup>2</sup> |
| C. | 0.76 kg/cm<sup>2</sup> |
| D. | 0.60 kg/cm<sup>2</sup> |
| Answer» B. 0.70 kg/cm<sup>2</sup> | |
| 6. |
Frictional stresses are developed due to ______ |
| A. | Relative movement of the base |
| B. | Relative movement of the slab |
| C. | Daily temperature variation |
| D. | Seasonal temperature variation |
| Answer» E. | |
| 7. |
What is the equation used to compute the frictional stresses in the rigid pavement? |
| A. | (S_f= frac{Lf}{2 10^4} ) |
| B. | (S_f= frac{wf}{2 10^4} ) |
| C. | (S_f= frac{wLf}{2 10^4} ) |
| D. | (S_f= frac{wLf}{2 10^5} ) |
| Answer» D. (S_f= frac{wLf}{2 10^5} ) | |
| 8. |
When does the warping of the cement concrete slab occur? |
| A. | Different temperature on layers |
| B. | Temperature differential exceeds 30 |
| C. | Same temperature on layers |
| D. | Temperature differential is below 10 |
| Answer» B. Temperature differential exceeds 30 | |
| 9. |
What are the type of stresses induced due to the temperature change in the pavement? |
| A. | Frictional stress and thermal stress |
| B. | Warping stress and thermal stress |
| C. | Warping stress and frictional stress |
| D. | Thermal stress and temporal stress |
| Answer» D. Thermal stress and temporal stress | |
| 10. |
The seasonal variation of temperature causes the variation in temperature across the depth of the slab. |
| A. | True |
| B. | False |
| Answer» C. | |
| 11. |
Temperature stresses in the pavement are caused due to the variation of temperature in ______ |
| A. | Slab |
| B. | Cement |
| C. | Subgrade |
| D. | Sub-base |
| Answer» B. Cement | |