MCQOPTIONS
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This section includes 5 Mcqs, each offering curated multiple-choice questions to sharpen your Robert Bosch knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The Boolean function Y= AB+XZ is to be made using only 2-input NAND gates.The minimum number of gates requires is |
| A. | 2 |
| B. | 3 |
| C. | 5 |
| D. | 6 |
| Answer» C. 5 | |
| 2. |
The two atomic operations permissible on semaphores are : (choose two) |
| A. | wait |
| B. | Signal |
| C. | None of these |
| D. | Both (a) and (b) |
| Answer» E. | |
| 3. |
What is the output of this C code? #include void foo(const int *); int main() { const int j = 20; printf("%d ", j); foo(&j); printf("%d", j); } void foo(const int *j) { *j = 500; } |
| A. | Compile time error |
| B. | 10 20 |
| C. | Undefined value |
| D. | 10 |
| Answer» B. 10 20 | |
| 4. |
The input to a coherent detector is DSB-SC signal plus noise. The noise at the detector output is |
| A. | the in-phase component |
| B. | the quadrature-component |
| C. | The envelope |
| D. | Zero |
| Answer» B. the quadrature-component | |
| 5. |
Consider the Amplitude Modulated (AM) signal Ac cosωct + 2 cos ωmt cosωct. For demodulating the signal using envelope detector, the minimum value of Ac should be |
| A. | 2 |
| B. | 1 |
| C. | 0.5 |
| D. | Zero |
| Answer» B. 1 | |