 
			 
			MCQOPTIONS
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				This section includes 11 Mcqs, each offering curated multiple-choice questions to sharpen your Network Theory knowledge and support exam preparation. Choose a topic below to get started.
| 1. | A lattice phase equalizer is a constant equalizer which satisfies the equation? | 
| A. | Z1Z2 = Ro | 
| B. | Z1 + Z2 = Ro | 
| C. | 1/Z1+1/Z2 = Ro | 
| D. | Z1Z2 = Ro2 | 
| Answer» E. | |
| 2. | The bridged-T phase equalizer consists of? | 
| A. | Only pure inductors | 
| B. | Only pure capacitors | 
| C. | Only pure resistors | 
| D. | Only pure reactance | 
| Answer» E. | |
| 3. | The attenuation is not sharp in the stop band for an m-derived filter. | 
| A. | True | 
| B. | False | 
| Answer» C. | |
| 4. | The propagation constant of a symmetrical T-section and π-section are the same. | 
| A. | True | 
| B. | False | 
| Answer» B. False | |
| 5. | The value of N in shunt equalizer is? | 
| A. | 1+ X12/Ro2 | 
| B. | X12/Ro2 | 
| C. | 1+ Ro2/X12 | 
| D. | Ro2/X12 | 
| Answer» D. Ro2/X12 | |
| 6. | What is the power at the load of a shunt equalizer? | 
| A. | [(Vmax2 X12)/(Ro(Ro2+X12))] | 
| B. | [(Vmax2 X12)/(2Ro(Ro2+X12))] | 
| C. | [(Vmax2 X12)/(3Ro(Ro2+X12))] | 
| D. | [(Vmax2 X12)/(4Ro(Ro2+X12))] | 
| Answer» E. | |
| 7. | What is the load current in terms of Vmax in the shunt equalizer? | 
| A. | (VmaxjX1)/(Ro(2Ro+jX1)) | 
| B. | (VmaxjX1)/(2Ro(2Ro+jX1)) | 
| C. | (VmaxjX1)/(2Ro(Ro+jX1)) | 
| D. | (VmaxjX1)/(Ro(Ro+jX1)) | 
| Answer» D. (VmaxjX1)/(Ro(Ro+jX1)) | |
| 8. | THE_VALUE_OF_N_IN_SHUNT_EQUALIZER_IS??$ | 
| A. | 1+ X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> | 
| B. | X<sub>1</sub><sup>2</sup>/R<sub>o</sub><sup>2</sup> | 
| C. | 1+ R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> | 
| D. | R<sub>o</sub><sup>2</sup>/X<sub>1</sub><sup>2</sup> | 
| Answer» E. | |
| 9. | The input power in shunt equalizer is? | 
| A. | V<sub>max</sub><sup>2</sup>/R<sub>o</sub> | 
| B. | V<sub>max</sub><sup>2</sup>/2R<sub>o</sub> | 
| C. | V<sub>max</sub><sup>2</sup>/3R<sub>o</sub> | 
| D. | V<sub>max</sub><sup>2</sup>/4R<sub>o</sub> | 
| Answer» E. | |
| 10. | What is the load current in terms of source current in the shunt equalizer? | 
| A. | I<sub>s</sub> jX<sub>1</sub>/(R<sub>o</sub>+jX<sub>1</sub>) | 
| B. | I<sub>s</sub> jX<sub>1</sub>/(R<sub>o</sub>+2jX<sub>1</sub>) | 
| C. | I<sub>s</sub> jX<sub>1</sub>/(2R<sub>o</sub>+2jX<sub>1</sub>) | 
| D. | I<sub>s</sub> jX<sub>1</sub>/(2R<sub>o</sub>+jX<sub>1</sub>) | 
| Answer» E. | |
| 11. | In the shunt equalizer, the current flowing from the source is? | 
| A. | V<sub>max</sub>(2R<sub>o</sub>+jX<sub>1</sub>)/2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>) | 
| B. | V<sub>max</sub>(R<sub>o</sub>+jX<sub>1</sub>)/R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>) | 
| C. | V<sub>max</sub>(R<sub>o</sub>+jX<sub>1</sub>)/2R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>) | 
| D. | V<sub>max</sub>(2R<sub>o</sub>+jX<sub>1</sub>)/R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>) | 
| Answer» B. V<sub>max</sub>(R<sub>o</sub>+jX<sub>1</sub>)/R<sub>o</sub>(R<sub>o</sub>+jX<sub>1</sub>) | |