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This section includes 6 Mcqs, each offering curated multiple-choice questions to sharpen your Chemical Engineering knowledge and support exam preparation. Choose a topic below to get started.
1. |
Which of the following constants is a type of equilibrium constant? |
A. | Dissociation constant |
B. | Association constant |
C. | Solubility |
D. | Decay constant |
Answer» E. | |
2. |
Which of the following is true for the rate law of a reversible reaction? |
A. | It reduces to irreversible form when product concentration is zero |
B. | It satisfies thermodynamic relationships at all times |
C. | Rate law can be written only in terms of partial pressures |
D. | Rate law can be written only in terms of concentrations |
Answer» B. It satisfies thermodynamic relationships at all times | |
3. |
For the reaction ½ A + 3B → 2Cthe specific reaction rate will be maximum for which species? |
A. | A |
B. | B |
C. | C |
D. | Equal for all species |
Answer» C. C | |
4. |
The equilibrium constant increases when _____________ |
A. | Initial concentration of reactant increases in endothermic reactions |
B. | Initial concentration of reactant decreases in endothermic reactions |
C. | Temperature increases in exothermic reactions |
D. | Temperature decreases in exothermic reactions |
Answer» E. | |
5. |
Choose the correct rate law for the set of elementary reactions. 2A ⇌ B + C [k1,-k2] A + 5B → 6D [k3] 3C + 2D + B ⇌ 6E [k4, -k5] 5A + 3E ⇌ 2R [k6] |
A. | –rA = k1CA2 – k2CB2CC – k3CACB5 – k6CA5CE3 |
B. | –rA = k1CA2 – k2CB2CC + k3CACB5 – k6CA5CE3 |
C. | –rA = k1k4CACCCD – k2k5CE3 + k3k6CA6CB5CE3 |
D. | –rA = k1k4CACCCD – k2k5CE3 – k3k6CA6CB5CE3 |
Answer» C. –rA = k1k4CACCCD – k2k5CE3 + k3k6CA6CB5CE3 | |
6. |
Choose the correct rate law for the elementary reversible reaction 3A ⇌ B + 2C. |
A. | –rA = kCA3 – CBCC2/KC |
B. | –rA = k[CA3 – CBCC2KC] |
C. | –rA = k[CA3 – CBCC2]/KC |
D. | –rA = k[CA3 – CBCC2/KC] |
Answer» E. | |