MCQOPTIONS
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MCQOPTIONS
This section includes 17 Mcqs, each offering curated multiple-choice questions to sharpen your Distillation Design knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Underwood’s equation can be used to find |
| A. | Distributed components |
| B. | Non distributed components |
| C. | Reflux for components |
| D. | Non reflux components |
| Answer» B. Non distributed components | |
| 2. |
If Component is distributed, then |
| A. | 0< DR> 1 |
| B. | 0< DR< 1 |
| C. | DR= 0 |
| D. | DR < 0 |
| Answer» C. DR= 0 | |
| 3. |
If Component is non-distributed, then |
| A. | DR >1 |
| B. | DR<1 |
| C. | DR=0 |
| D. | DR=∞ |
| Answer» B. DR<1 | |
| 4. |
Calculate ln S? If XLK=0.41 and XHK = 0.005 and XL= 0.417 and XH= 0.01, then |
| A. | 9.45 |
| B. | 8.90 |
| C. | 8.137 |
| D. | 7.98 |
| Answer» D. 7.98 | |
| 5. |
N√αN this equation is called as |
| A. | Sorel’s Method |
| B. | Polson Equation |
| C. | Fenske’s Equation |
| D. | Gilliland Equation |
| Answer» D. Gilliland Equation | |
| 6. |
The term S in the Fenske’s equation, is given as |
| A. | (xLKxHK)D(xLKxHK)B |
| B. | (xLKxHK)D(xLKxHK)L(xLKxHK)R |
| C. | (xLKxHK)L(xLKxHK)V |
| D. | (xLKxHK)HK(xLKxHK)LK |
| Answer» B. (xLKxHK)D(xLKxHK)L(xLKxHK)R | |
| 7. |
Fenske’s Equation can be written as |
| A. | Nmin = S/ ln α |
| B. | Nmin = ln S/ ln α |
| C. | Nmin – 1 = ln S/ ln α |
| D. | Nmin + 1 = ln S/ ln α |
| Answer» C. Nmin – 1 = ln S/ ln α | |
| 8. |
IF_COMPONENT_IS_DISTRIBUTED,_THEN?$ |
| A. | 0< D<sub>R</sub>> 1 |
| B. | 0< DR< 1 |
| C. | DR= 0 |
| D. | DR < 0 |
| Answer» C. DR= 0 | |
| 9. |
Underwood’s_equation_can_be_used_to_find$# |
| A. | Distributed components |
| B. | Non distributed components |
| C. | Reflux for components |
| D. | Non reflux components |
| Answer» B. Non distributed components | |
| 10. |
If Component is non-distributed, the? |
| A. | D<sub>R</sub> >1 |
| B. | D<sub>R</sub><1 |
| C. | DR=0 |
| D. | DR=‚àû |
| Answer» B. D<sub>R</sub><1 | |
| 11. |
Most distillation columns are designed for reflux ratio between |
| A. | 3 to 5 R<sub>min</sub> |
| B. | 1.2 and 1 .7 R<sub>min</sub> |
| C. | 2 to 10 R<sub>min</sub> |
| D. | 0.2 to 0.7 R<sub>min</sub> |
| Answer» C. 2 to 10 R<sub>min</sub> | |
| 12. |
In a distillation operation, the reflux ratio may vary between |
| A. | Zero and one |
| B. | Zero and infinity |
| C. | Minimum and infinity |
| D. | One and two |
| Answer» B. Zero and infinity | |
| 13. |
A non-key component may be distributed if |
| A. | Close to that of one key |
| B. | The Specified separation is sloppy |
| C. | Intermediate between keys |
| D. | Intermediate one key |
| Answer» C. Intermediate between keys | |
| 14. |
Calculate ln S? If XLK=0.41 and XHK = 0.005 and XL= 0.417 and XH= 0.01, then |
| A. | 9.45 |
| B. | 8.90 |
| C. | 8.137 |
| D. | 7.98 |
| Answer» D. 7.98 | |
| 15. |
N√αN this equation is called as$ |
| A. | Sorel’s Method |
| B. | Polson Equation |
| C. | Fenske’s Equation |
| D. | Gilliland Equation |
| Answer» D. Gilliland Equation | |
| 16. |
The term S in the Fenske’s equation, is given as$ |
| A. | (x<sub>LK</sub>x<sub>HK</sub>)D(x<sub>LK</sub>x<sub>HK</sub>)B |
| B. | (x<sub>LK</sub>x<sub>HK</sub>)D(x<sub>LK</sub>x<sub>HK</sub>)L(x<sub>LK</sub>x<sub>HK</sub>)R |
| C. | (x<sub>LK</sub>x<sub>HK</sub>)L(x<sub>LK</sub>x<sub>HK</sub>)V |
| D. | (x<sub>LK</sub>x<sub>HK</sub>)HK(x<sub>LK</sub>x<sub>HK</sub>)LK |
| Answer» B. (x<sub>LK</sub>x<sub>HK</sub>)D(x<sub>LK</sub>x<sub>HK</sub>)L(x<sub>LK</sub>x<sub>HK</sub>)R | |
| 17. |
Fenske’s Equation can be written as |
| A. | N<sub>min</sub> = S/ ln α |
| B. | N<sub>min</sub> = ln S/ ln α |
| C. | N<sub>min</sub> – 1 = ln S/ ln α |
| D. | N<sub>min</sub> + 1 = ln S/ ln α |
| Answer» C. N<sub>min</sub> ‚Äö√Ñ√∂‚àö√ë‚àö¬® 1 = ln S/ ln ‚âà√≠¬¨¬± | |