MCQOPTIONS
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MCQOPTIONS
This section includes 10 Mcqs, each offering curated multiple-choice questions to sharpen your Air Conditioning knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The value of BPF for the heating and the cooling coil is different under the same temperature conditions. |
| A. | True |
| B. | False |
| Answer» C. | |
| 2. |
A coil with low BPF has better performance. |
| A. | True |
| B. | False |
| Answer» B. False | |
| 3. |
What is the contact factor for cooling coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature? |
| A. | td1 – td2 / td1 – td3 |
| B. | td2 – td1 / td3 – td1 |
| C. | td3 – td2 / td2 – td1 |
| D. | td3 – td2 / td1 – td2 |
| Answer» B. td2 – td1 / td3 – td1 | |
| 4. |
What is the contact factor for heating coil, if td1 = temperature at entry, t2 = temperature at exit and td3 = coil temperature? |
| A. | td3 – td1 / td3 – td1 |
| B. | td2 – td1 / td3 – td1 |
| C. | td3 – td2 / td2 – td1 |
| D. | td3 – td2 / td1 – td2 |
| Answer» C. td3 – td2 / td2 – td1 | |
| 5. |
What is the efficiency of the coil? |
| A. | 1 + BPF |
| B. | 1 / BPF |
| C. | BPF |
| D. | 1 – BPF |
| Answer» E. | |
| 6. |
What is the formula of logarithmic mean temperature in terms of By-pass factor? |
| A. | Tm = td2 – td1 / loge [1/BPF] |
| B. | Tm = td2 – td1 / log10 [BPF] |
| C. | Tm = td2 – td1 / loge [BPF] |
| D. | Tm = td2 – td3 / loge [BPF] |
| Answer» D. Tm = td2 – td3 / loge [BPF] | |
| 7. |
What is the value of sensible heat given out by the coil? |
| A. | U Ac tm |
| B. | U Ac |
| C. | U tm |
| D. | U Ac2 tm |
| Answer» B. U Ac | |
| 8. |
If the value of BPF for one row of a coil is y then what is the value of BPF for n similar rows? |
| A. | n / y |
| B. | n + y |
| C. | (y)n |
| D. | n x y |
| Answer» D. n x y | |
| 9. |
What is the By-pass factor for cooling coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature? |
| A. | td3 – td1 / td3 – td1 |
| B. | td3 – td2 / td3 – td1 |
| C. | td3 – td2 / td2 – td1 |
| D. | td2 – td3 / td1 – td3 |
| Answer» E. | |
| 10. |
What is the By-pass factor for heating coil, if td1 = temperature at entry, td2 = temperature at exit and td3 = coil temperature? |
| A. | td3 – td1 / td3 – td1 |
| B. | td3 – td2 / td3 – td1 |
| C. | td3 – td2 / td2 – td1 |
| D. | td3 – td2 / td1 – td2 |
| Answer» C. td3 – td2 / td2 – td1 | |