

MCQOPTIONS
Saved Bookmarks
This section includes 13 Mcqs, each offering curated multiple-choice questions to sharpen your Digital Signal Processing knowledge and support exam preparation. Choose a topic below to get started.
1. |
What is the z-transform of the signal x(n)=[5(3n)-9(7n)]u(n)? |
A. | \(\frac{5}{1-3z^{-1}}-\frac{9}{1-7z^{-1}}\) |
B. | \(\frac{5}{1+3z^{-1}}-\frac{9}{1+7z^{-1}}\) |
C. | \(\frac{5}{1-3z}-\frac{9}{1-7z}\) |
D. | None of the mentioned |
Answer» B. \(\frac{5}{1+3z^{-1}}-\frac{9}{1+7z^{-1}}\) | |
2. |
What is the z-transform of the signal defined as x(n)=u(n)-u(n+N)? |
A. | \(\frac{1+z^N}{1+z^{-1}}\) |
B. | \(\frac{1-z^N}{1-z^{-1}}\) |
C. | \(\frac{1+z^{-N}}{1+z^{-1}}\) |
D. | \(\frac{1-z^{-N}}{1-z^{-1}}\) |
Answer» E. | |
3. |
What is the z-transform of the signal x(n)=cos(jω0n)u(n)? |
A. | \(\frac{z^{-1} sin\omega_0}{1+2z^{-1} cosω_0+z^{-2}}\) |
B. | \(\frac{z^{-1} sin\omega_0}{1-2z^{-1} cosω_0-z^{-2}}\) |
C. | \(\frac{1-z^{-1} cos\omega_0}{1-2z^{-1} cosω_0+z^{-2}}\) |
D. | \(\frac{z^{-1} sin\omega_0}{1-2z^{-1} cosω_0+z^{-2}}\) |
Answer» D. \(\frac{z^{-1} sin\omega_0}{1-2z^{-1} cosω_0+z^{-2}}\) | |
4. |
If x1(n)={1,2,3} and x2(n)={1,1,1}, then what is the convolution sequence of the given two signals? |
A. | {1,2,3,1,1} |
B. | {1,2,3,4,5} |
C. | {1,3,5,6,2} |
D. | {1,2,6,5,3} |
Answer» E. | |
5. |
What is the signal whose z-transform is given as X(z)=\(\frac{1}{2πj} \oint X_1 (v) X_2 (\frac{z}{v})v^{-1} dv\)? |
A. | x1(n)*x2(n) |
B. | x1(n)*x2(-n) |
C. | x1(n).x2(n) |
D. | x1(n)*x2*(n) |
Answer» D. x1(n)*x2*(n) | |
6. |
If x(n) is an imaginary sequence, then the z-transform of the real part of the sequence is? |
A. | \(\frac{1}{2}\)[X(z)+X*(z*)] |
B. | \(\frac{1}{2}\)[X(z)-X*(z*)] |
C. | \(\frac{1}{2}\)[X(-z)-X*(z*)] |
D. | \(\frac{1}{2}\)[X(-z)+X*(z*)] |
Answer» B. \(\frac{1}{2}\)[X(z)-X*(z*)] | |
7. |
If X(z) is the z-transform of the signal x(n), then what is the z-transform of x*(n)? |
A. | X(z*) |
B. | X*(z) |
C. | X*(-z) |
D. | X*(z*) |
Answer» E. | |
8. |
If Z{x(n)}=X(z) and the poles of X(z) are all inside the unit circle, then the final value of x(n) as \(n\rightarrow\infty\) is given by i.e., \(\lim_{n\rightarrow\infty}\)x(n)=? |
A. | \(\lim_{z \rightarrow 1} [(z-1) X(z)] \) |
B. | \(\lim_{z \rightarrow 0} [(z-1) X(z)] \) |
C. | \(\lim_{z \rightarrow -1} [(z-1) X(z)] \) |
D. | \(\lim_{z \rightarrow 1} [(z+1) X(z)] \) |
Answer» B. \(\lim_{z \rightarrow 0} [(z-1) X(z)] \) | |
9. |
If x(n) is causal, then \(\lim_{z\rightarrow\infty}\) X(z)=? |
A. | x(-1) |
B. | x(1) |
C. | x(0) |
D. | Cannot be determined |
Answer» D. Cannot be determined | |
10. |
If Z{x1(n)}=X1(z) and Z{x2(n)}=X2(z) then what is the z-transform of correlation between the two signals? |
A. | X1(z).X2(z-1) |
B. | X1(z).X2(z-1) |
C. | X1(z).X2(z) |
D. | X1(z).X2(-z) |
Answer» C. X1(z).X2(z) | |
11. |
What is the convolution x(n) of the signals x1(n)={1,-2,1} and x2(n)={1,1,1,1,1,1}? |
A. | {1,1,0,0,0,0,1,1} |
B. | {-1,-1,0,0,0,0,-1,-1} |
C. | {-1,1,0,0,0,0,1,-1} |
D. | {1,-1,0,0,0,0,-1,1} |
Answer» E. | |
12. |
If Z{x1(n)}=X1(z) and Z{x2(n)}=X2(z) then Z{x1(n)*x2(n)}=? |
A. | X1(z).X2(z) |
B. | X1(z)+X2(z) |
C. | X1(z)*X2(z) |
D. | None of the mentioned |
Answer» B. X1(z)+X2(z) | |
13. |
What is the signal x(n) whose z-transform X(z)=log(1+az-1);|z|>|a|? |
A. | \((-1)^n.\frac{a^n}{n}.u(n-1)\) |
B. | \((-1)^n.\frac{a^n}{n}.u(n+1)\) |
C. | \((-1)^{n-1}.\frac{a^n}{n}.u(n-1)\) |
D. | \((-1)^{n-1}.\frac{a^n}{n}.u(n+1)\) |
Answer» D. \((-1)^{n-1}.\frac{a^n}{n}.u(n+1)\) | |